Variable in variable's name for reference

['AnKo]

Hey guys, thx for the time you spent clicking here :D

My question is simple enough. Let me give a basic example though:

char a1[]="ok";
char a2[]="yes";
char a3[]="right";
for (int n=1;n<=3;n++;)
    cout << a<n>;

Is there some way to make this concept work?

Any help much appreciated!

[np complete]

I don't think so this can be implemented. Perhapes this may be close to what you want.

You can do something like this using 2 dimensional array. Here is a code snippet.

char a[][7]={"ok","yes","right"};

    for(int i=0; i<3; i++)
    {
        for(int j=0 ; j<7 ; j++)
          cout<< a[i][j];
    }

[Ancient Dragon]

you don't need that second loop

for(int i = 0; i < 3; i++)
   cout << a[i] << '\n';

[dospy]

i think he wants to know that if there is a way to output variables with a loop statement which contains only one instruction whithin the brackets like this:

int age = 32;
char name[50] = "Pickatchu";
double height = "1.65";

for(int i = 0; i < 3; i++)
{
    cout << ..... << endl;
}

something instead of "....." to output:

32
Pickatchu
1.65

the simple answer is no
there is altho a way aroud this but is too unconvinient(overhead)

[Ancient Dragon]

The way to make the concept work is to use an array instead of individual variable names. If the program already has individual variable names then to use a loop you could create an array of pointers that point to each of the individual variables, something like this:

char a1[]="ok";
char a2[]="yes";
char a3[]="right";
char* names[] = {a1,a2,a3,NULL};
for (int n = 0; names[n] != NULL;n++;)
    cout << names[n] << '\n';