Hi! I'm having a project where I must give 2 integers and divide them. I must use the NumberFormatException to make sure that those two numbers are only integers( and display a message when they aren't) and the ArithmeticException to make sure that the can be divided (and display amessage when the denominator is equal to zero.Here's the code that I've written:

``````import java.util.Scanner;
import java.lang.*;
public class Division{

public static void main(String[] args){
Scanner input=new Scanner(System.in);
System.out.println("Enter first number:");
String number1=input.nextLine();

try{
int a=Integer.parseInt(number1);}

catch(NumberFormatException nfe){
System.out.println("Must enter an integer!");
return;}

System.out.println("Enter second number:");
String number2=input.nextLine();

try{
int b=Integer.parseInt(number2);}

catch(NumberFormatException nfe){
System.out.println("Must enter an integer!");
return;}

try{
int a=Integer.parseInt(number1);
int b=Integer.parseInt(number2);
double newa=(double)a;
double newb=(double)b;
double division=newa/newb;

System.out.println("Division outcome:"+division);}

catch(ArithmeticException DivZero){
System.out.println("Cannot divide by zero!");}

}
}
``````

My programm works fine when the two numbers are integers, as well as when one of them isn't. But when a give a value of zero for b-the denominator, instead of getting the 'Cannot divide by zero", I get the Division outcome:infinity...

tried throwing the exception if newb = 0?

## All 3 Replies

tried throwing the exception if newb = 0?

In the Java Language Specification I read the following:

"The result of a floating-point division is determined by the specification of IEEE arithmetic:"
...
"Division of a nonzero finite value by a zero results in a signed infinity."

(Source: JLS - 15.17.2 Division Operator)

Ok, now I've got it! I perform the division with both numbers been integers and I get the ArithmeticException as I want it! Thank you very much!

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