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`t_C lt t_A lt t_C``t_c=t_A=t_C``t_c=t_Altt_c` `t_B lt t_A = t_C`

Answer :

BSolution :

Work done by gravity on A & B is same. <br> `therefore` Horizontal velocity of A = horizontal velocity of B as they leave the horizontal portion of the structure <br> `therefore t_A=t_B……(i)` <br> Also vertical velocity of A & vertical velocity of C when released are both zero <br> `therefore` They both will cover same vertical distance in same time <br> `therefore t_A=t_C....(ii)` <br> From (i) & (ii) <br> `t_A=t_B=t_C` <br> Note : Correction in option option B should be <br> `t_A=t_B=t_C`