hello friend
i want to make java program to slove trigomeric eq but i dont know how to stare as i m new in java i don't 9 how trigomeric eq can slove bye java can u tell me how i should thikg logicaly i need u r logical help so i can write my code with help that logic.:sad: plz help me so that i can write code by myself.

Example 1: [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img1.gif[/IMG]

There are an infinite number of solutions to this problem. To solve for x, you must first isolate the sine term.

[IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img2.gif[/IMG]


We know that the [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img3.gif[/IMG]therefore [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img4.gif[/IMG] The sine function is positive in quadrants I and II. The [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img5.gif[/IMG]is also equal to [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img6.gif[/IMG] Therefore, two of the solutions to the problem are [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img7.gif[/IMG] and [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img8.gif[/IMG]


The period of the sin [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img9.gif[/IMG] function is [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img10.gif[/IMG] This means that the values will repeat every [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img11.gif[/IMG] radians in both directions. Therefore, the exact solutions are [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img12.gif[/IMG] and [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img13.gif[/IMG] where n is an integer. The approximate solutions are [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img14.gif[/IMG] and [IMG]http://www.sosmath.com/algebra/solve/solve9/s91/img15.gif[/IMG] where n is an integer.
note:this is one ex of trignometric eq.

You need to import the java math package, (import java.lang.Math)

use the method sin(). It takes doubles.

Eg.

double x = //something
double answer = sin(x);
answer = 2*answer - 1;
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