105(decimal) = 01101001(binary)
for example, i want to skip first 3 bits of binary and get the number to the right and assign it to an integer:
01001(binary) = 9 (decimal)
could you plz give a little code sample?
thanx.
105(decimal) = 01101001(binary)
for example, i want to skip first 3 bits of binary and get the number to the right and assign it to an integer:
01001(binary) = 9 (decimal)
could you plz give a little code sample?
thanx.
Hi,
Its simple,
1. Just use the shift operator. First n times left shift and then again n times right shift. This will make all zeroes in beginning.
int sourceNo=105, destNo;
int n;
destNo = sourceNo<<n; // Here n is the number of bits you want to skip.
destNo = destNo >> n;
2. the number of bits you want to skip, just do a Bitwise AND with that number of Zeroes. Please find the code below.
int souceNo=105, destNo;
int andMask = ~0;
andMask = andMask >>n; // Here n is the number of bits you want to skip.
destNo = sourceNo & andMask;
.
>>destNo = sourceNo<<n; // Here n is the number of bits you want to skip.
Here, the value of n is undefined because you didn't initialize it to anything in the previous line :)
105(decimal) = 01101001(binary)
for example, i want to skip first 3 bits of binary and get the number to the right and assign it to an integer:
01001(binary) = 9 (decimal)
could you plz give a little code sample?
thanx.
Set a mask to clear the first 3 bits:
int mask = 0x1F; // binary 00011111
newint = oldint & mask;
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