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Heres an example since A is a square matrix while B and C is not. The program on my head is a row and a colum counter then if the row and colum is equal to eachother then the system will print out that the A matrix is a square matrix and both B and C are not. Is their efficent way on doing this?

            {7, 2, 1}, 
A =         {0, 4, 2},
            {5, 7,11}                                  {1        },  
                                                   C = {2,  3,  4},
                                                       {5,  6    }
          {1, 4},
B =       {2, 8},
          {1, 6,}
Edited by C_Oleyers
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  • Latest Post Latest Post by JamesCherrill
Member Avatar for JamesCherrill

If you store it as a 2D array in Java then it's easy.
Remember htat a 2D array is really an array of arrays, so all you need is the check that the length of each inner array is the same as the length of the outer array. No need to count anything. You won't find anything more efficient than that.

Edited by JamesCherrill
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