Okay, here goes. Learning PHP and am having trouble building a program that would let a client insert inventory in the database without having any knowledge of MySQL or PHP.

Here is what I have so far:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title>Add A Piece To The Inventory!</title>


<form action="upload.php" method="post">

<input type="text" name="name" maxlength="60" />Name<br>&nbsp;<br>
<input type="text" name="category" maxlength="20" />Category<br>&nbsp;<br>
<input type="text" name="type" maxlength="20" />Type<br>&nbsp;<br>
<input type="text" name="description" maxlength="80" />Description<br>&nbsp;<br>
<input type="text" name="price" maxlength="10" />Price<br>&nbsp;<br>
<input type="submit" value="Upload New Item" />



Okay so that's what they are going to see and that works fine...now here's upload.php

$cxn = mysqli_connect ("localhost","orbit","******","storeinventory")
or die ("Could not connect"); ?>

$name = $_POST;
$category = $_POST;
$type = $_POST;
$description = $_POST;
$price = $_POST;

$query = 'INSERT INTO `productlists` (`prod_number`, `name`, `category`, `type`, `description`, `price`, `pix`) VALUES (\'\', \'name\', \'category\', \'type\', \'description\', \'price\', \'\') WHERE (name="$name",category="$category",type="$type",description="$description",price="$price")';
$result = mysqli_query($cxn,$query)
or die("Couldn't execute query");


echo "Hit the BACK button to insert another item"

I get the "Couldn't execute query" everytime I try this. Please help. Yes, I know I missing something. Yes I have done something wrong. What is it though? I have tried for about 18 hours to figure this out.

$con = mysql_connect("localhost","root","");
if (!$con)
  die('Connection Error ' . mysql_error());

mysql_select_db("my_db", $con);

$sql="INSERT INTO productlists (prod_number, name, category, type, description, price, pix)
('$_POST[prod_number]','$_POST[name]','$_POST[category]','$_POST[type]','$_POST[description]','$_POST[price]', '$_POST[pix]')";

if (!mysql_query($sql,$con))
  die('Error: ' . mysql_error());
echo ""Hit the BACK button to insert another item"";


:?: try this .. I don't know why you used all these single quotes, slashes .. but what i know is that your code should look something like this .. give it a try ..

all the best ..

commented: ah! moti ! tum kabse php forum visit karne lagi ! moti with glasses! lol..that would be funny! +4

Thank you so much! After toying with your code for about twenty seconds it works perfectly! Again thanks and you all will probably see me back here asking more questions!