I don't know anything about PHP but my site has a ready made template with the following block of code which produces an image stored on my server and links to page on my site:
<block type="core/template" after="-" name="left.permanent.callout-2" template="callouts/left_col.phtml"> <action method="setImgSrc"><src>images/media/col_left_callout-2.jpg</src></action> <action method="setImgAlt" translate="alt" module="catalog"><alt>Our customer service is available 24/7. Call us at (800) DEMO-NUMBER.</alt></action> <action method="setLinkUrl"><url>checkout/cart</url></action> </block>
Instead of doing this am trying to use the following code which uses an image on another website and links to another website.
<a href="http://mats.silvertap.com/Tracking/Tracking.aspx?t=2&a=6908&p=31&u=9214&i=2976"><img border="0" src="http://mats.silvertap.com/Tracking/Tracking.aspx?t=1&a=6908&p=31&u=9214&i=2976" /></a>
If tried just simply replacing the code but it doesn't work for some reason. Can anyone point me in the right direction here (I hope that I have provided all the information thats required).
Any help is much appreciated