PHP random number check

[rajeesh_rsn]

Hai,

I had a small doubt in my php script.
I need to select 10 random numbers from a range ( for eg: 2-88) and stored it in an array.
For eg: $number=rand(2,88); This returns only one value from the range 2-88. I need 15 random numbers from the given range and also I need 15 different numbers and finally stored it in an array. ie $number[1],$number[2] .......

Please help me .... Thanks in Advance
Rajeesh

[tuse]

1. Keep an array to hold the random numbers

2. In order to add an element to this array, generate a random number in the required range, and check the array to see if the generated number is already a part of the array (using foreach)

3. If the generated random number is not a part of the array, append it to the array, else goto step 2.

4. Finish the algorithm when the array holds 15 elements

----

Alternatively, you can use 'in_array()' to check if a value exists in an array

http://www.w3schools.com/PHP/func_array_in_array.asp

[rajesh_kanna]

This code will help you in retrieving 15 random numbers and storing them in an array,.....

<?php 
 $j = 0;
 $data = array();
 while($j < 15)
 {
  $value = rand(2,88);
  if(!(in_array($value,$data))) 
  { $j = $j + 1;
  $data[$j] = $value; }
 }
foreach($data as $keys)
{ echo $keys."<br>"; }
 ?>

You use this code to get 15 random numbers and you code to select 10 nums as you wish,..