Hi

I am an turkish student trying to got understood of java ajax complition..

I have checked out the hole threads but cant see or ı have missed it up.

SO here is my problem.

I have a blog in blogspot. so in an post. ı want to do something like this.

İn the post ı have a code with "java" center of the post or where ever. and is with clicking on this code or something jpeg or video etc but with javascripted.. ı want to call the posts real content.. but without clicking that. ı dont want to show up the content.

so is ; if u click you wıll get the content ..if you not. you wont get it until you cilck it :)

p.s; sorry for my poor english. ı am so new on these coding part and trying to figure out the idea of it.

In other words, you want to load content when someone clicks an image, was it? That's not that hard, but doing so in a blog which you do not control the server-scripting might be a pain. I don't event think it's possible to add scripts to those blogs-system (this is to prevent XSS).

Anyway. If you have control over the server-scripting you would do something like this:

function loadContent()
{
    var loader = new XMLHttpRequest();
    loader.open("contentpage.php");
    loader.onreadystatechange = function()
    {
        if(loader.readyState == 4)
            document.getElementById('contentDiv').innerHTML = loader.responseText;
    }
    loader.send();
}

And for html:

<html>
<head>........</head>
<body>
   <div id="contentDiv"></div>
   <img src="somimage.png" onclick="loadContent();" />
</body>

And that's it. Might have some typo's though.
HTH

--
/Alxandr

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