Hi, everybody. I've been a member for a while, but I'm not a coder, so I haven't made any posts.

But I get frustrated not knowing how to do things. So I'm taking the plunge.

I'm working through a tutorial on PHP and MySQL (here: http://dev.mysql.com/tech-resources/articles/ddws/), and things have been going fine, right up until I try to write to the database using a form.

I've tried all the code and checked everything, and honestly, I'm starting to wonder whether there's a mistake in the code. I copied and pasted the code given on the site, and that doesn't seem to work either.

The code I'm using doesn't give an error; I click 'Submit', and the page reloads. When I check the database, the new information isn't in there.

Any pointers? Or any other tutorials you know of to work through? I'm basically just trying to learn how to build a MySQL database.

Thanks in advance. :)

<HTML>
<HEAD>
<TITLE>Gettin' Bizzy</TITLE>
<link rel="stylesheet" type="text/css" href="stylesheet.css">
</HEAD>
<BODY>
<H1>Test Page</H1>
<P>Server says! Today is 
  <?php
  echo( date("l, F dS, Y.") );
?>
<?php

//First, connect to the database:

$dbconnect = mysql_connect("localhost", "myusername", "mypassword");

//Just in case there's a database connection problem, this will give an error message:

$dbconnect = @mysql_connect("localhost", "myusername", "mypassword");
if (!$dbconnect) {
echo( "<P>We're sorry. We cannot connect to the " .
"database server right now.</P>" );
exit();
}

//This chooses which database to use:

mysql_select_db("myusername_dbname", $dbconnect);

//And again, in case there are any connection problems, this gives an error message:

if (! @mysql_select_db("myusername_dbname") ) {
echo( "<P>We're sorry. That " .
"database is not available right now.</P>" );
exit();
}
?>

<H2>Words</H2>
<P>Here are all the words in the database:</P>
<BLOCKQUOTE>
<?php 
//Request the actual words only
  $result = mysql_query(
            "SELECT Word FROM Dictionary");
  if (!$result) {
    echo("<P>Error performing query: " .
         mysql_error() . "</P>");
    exit();
  }

// Display each word in a paragraph
  while ( $row = mysql_fetch_array($result) ) {
    echo("<P>" . $row["Word"] . "</P>");
  }
?>

</BLOCKQUOTE>
<H2>Add a word to the dictionary</H2>

<FORM ACTION="<?php echo($PHP_SELF); ?>" METHOD=POST>
<P>Type your word here:<BR>
<TEXTAREA NAME="word" ROWS=2 COLS=40 WRAP></TEXTAREA><BR>
<INPUT TYPE=SUBMIT NAME="submitWord" VALUE="SUBMIT">
</FORM>

<?php
if ("SUBMIT" == $submitWord) {
  $sql = "INSERT INTO Dictionary SET " .
         "Word='$word', " .
         "AddDate=CURDATE()";
  if (mysql_query($sql)) {
    echo("<P>Your word has been added.</P>");
  } else {
    echo("<P>Error adding submitted word: " .
         mysql_error() . "</P>");
  }
}
?>

</BODY>
</HTML>

I cant see where are u retrieving the post variables before entering the word into the database.
ur insert statement

$sql = "INSERT INTO Dictionary SET " .
         "Word='$word', " .
         "AddDate=CURDATE()";

should be preceded by something like

$word = $_POST['word']; //or whatever is the name of ur input field

hope that helps..

Hi, everybody. I've been a member for a while, but I'm not a coder, so I haven't made any posts.

But I get frustrated not knowing how to do things. So I'm taking the plunge.

I'm working through a tutorial on PHP and MySQL (here: http://dev.mysql.com/tech-resources/articles/ddws/), and things have been going fine, right up until I try to write to the database using a form.

I've tried all the code and checked everything, and honestly, I'm starting to wonder whether there's a mistake in the code. I copied and pasted the code given on the site, and that doesn't seem to work either.

The code I'm using doesn't give an error; I click 'Submit', and the page reloads. When I check the database, the new information isn't in there.

Any pointers? Or any other tutorials you know of to work through? I'm basically just trying to learn how to build a MySQL database.

Thanks in advance. :)

<HTML>
<HEAD>
<TITLE>Gettin' Bizzy</TITLE>
<link rel="stylesheet" type="text/css" href="stylesheet.css">
</HEAD>
<BODY>
<H1>Test Page</H1>
<P>Server says! Today is 
  <?php
  echo( date("l, F dS, Y.") );
?>
<?php

//First, connect to the database:

$dbconnect = mysql_connect("localhost", "myusername", "mypassword");

//Just in case there's a database connection problem, this will give an error message:

$dbconnect = @mysql_connect("localhost", "myusername", "mypassword");
if (!$dbconnect) {
echo( "<P>We're sorry. We cannot connect to the " .
"database server right now.</P>" );
exit();
}

//This chooses which database to use:

mysql_select_db("myusername_dbname", $dbconnect);

//And again, in case there are any connection problems, this gives an error message:

if (! @mysql_select_db("myusername_dbname") ) {
echo( "<P>We're sorry. That " .
"database is not available right now.</P>" );
exit();
}
?>

<H2>Words</H2>
<P>Here are all the words in the database:</P>
<BLOCKQUOTE>
<?php 
//Request the actual words only
  $result = mysql_query(
            "SELECT Word FROM Dictionary");
  if (!$result) {
    echo("<P>Error performing query: " .
         mysql_error() . "</P>");
    exit();
  }

// Display each word in a paragraph
  while ( $row = mysql_fetch_array($result) ) {
    echo("<P>" . $row["Word"] . "</P>");
  }
?>

</BLOCKQUOTE>
<H2>Add a word to the dictionary</H2>

<FORM ACTION="<?php echo($PHP_SELF); ?>" METHOD=POST>
<P>Type your word here:<BR>
<TEXTAREA NAME="word" ROWS=2 COLS=40 WRAP></TEXTAREA><BR>
<INPUT TYPE=SUBMIT NAME="submitWord" VALUE="SUBMIT">
</FORM>

<?php
if ("SUBMIT" == $submitWord) {
  $sql = "INSERT INTO Dictionary SET " .
         "Word='$word', " .
         "AddDate=CURDATE()";
  if (mysql_query($sql)) {
    echo("<P>Your word has been added.</P>");
  } else {
    echo("<P>Error adding submitted word: " .
         mysql_error() . "</P>");
  }
}
?>

</BODY>
</HTML>

do you have a database created for it?
If not first create the database and check if you can connect to the mysql using

mysql_connect($server_name,$user,$password) or die(mysql_error());

I cant see where are u retrieving the post variables before entering the word into the database.
ur insert statement

$sql = "INSERT INTO Dictionary SET " .
         "Word='$word', " .
         "AddDate=CURDATE()";

should be preceded by something like

$word = $_POST['word']; //or whatever is the name of ur input field

hope that helps..

Thank you. I'll take a closer look.

do you have a database created for it?
If not first create the database and check if you can connect to the mysql using

mysql_connect($server_name,$user,$password) or die(mysql_error());

Yes, I have the database, and I am able to connect to it and retrieve data. I have tested the code I pasted above, and it retrieves the data just fine. I just can't send data to the database.

I'm going to try the suggestion above.

I appreciate the responses. :)

Okay, I've tried this:

<FORM ACTION="<?php echo($PHP_SELF); ?>" METHOD=POST>
<P>Type your word here:<BR>
<TEXTAREA NAME="word" ROWS=2 COLS=40 WRAP></TEXTAREA><BR>
<INPUT TYPE=SUBMIT NAME="submitWord" VALUE="SUBMIT">
</FORM>

<?php
$word = $_POST['submitWord'];
if ("SUBMIT" == $submitWord) {
  $sql = "INSERT INTO Dictionary SET " .
         "Word='$word', " .
         "AddDate=CURDATE()";
  if (mysql_query($sql)) {
    echo("<P>Your word has been added.</P>");
  } else {
    echo("<P>Error adding submitted word: " .
         mysql_error() . "</P>");
  }
}
?>

and for good measure, just to be sure, I tried this:

<FORM ACTION="<?php echo($PHP_SELF); ?>" METHOD=POST>
<P>Type your word here:<BR>
<TEXTAREA NAME="word" ROWS=2 COLS=40 WRAP></TEXTAREA><BR>
<INPUT TYPE=SUBMIT NAME="submitWord" VALUE="SUBMIT">
</FORM>

<?php
$word = $_POST['word'];
if ("SUBMIT" == $submitWord) {
  $sql = "INSERT INTO Dictionary SET " .
         "Word='$word', " .
         "AddDate=CURDATE()";
  if (mysql_query($sql)) {
    echo("<P>Your word has been added.</P>");
  } else {
    echo("<P>Error adding submitted word: " .
         mysql_error() . "</P>");
  }
}
?>

But neither worked--same result.

I appreciate the patience. I understand the concepts at work here, but I'm not completely certain of how the parts of the code are working together.

your code need lots of improvements like the insert query was wrong and the php too.Try this -

<FORM ACTION="<?php echo($PHP_SELF); ?>" METHOD="post">
<P>Type your word here:<BR>
<TEXTAREA NAME="word" ROWS="2" COLS="40" wrap="hard" ></TEXTAREA><BR>
<INPUT TYPE="SUBMIT" NAME="submitWord" VALUE="SUBMIT">
</FORM>

<?php
if ( isset($_POST["submitWord"]) && $_POST["submitWord"]!='')
{
	$word = $_POST['submitWord'];

  $sql = "INSERT INTO Dictionary (Word,AddDate) value( Word='".$word."',AddDate='".CURDATE()."')";
  if (mysql_query($sql)) {
    echo("<P>Your word has been added.</P>");
  } else {
    echo("<P>Error adding submitted word: " .
         mysql_error() . "</P>");
  }
}
?>

yeah gud point... bt network18 i believe instead of "value" it should be "values" in the query...

your code need lots of improvements like the insert query was wrong and the php too.Try this -

<FORM ACTION="<?php echo($PHP_SELF); ?>" METHOD="post">
<P>Type your word here:<BR>
<TEXTAREA NAME="word" ROWS="2" COLS="40" wrap="hard" ></TEXTAREA><BR>
<INPUT TYPE="SUBMIT" NAME="submitWord" VALUE="SUBMIT">
</FORM>

<?php
if ( isset($_POST["submitWord"]) && $_POST["submitWord"]!='')
{
	$word = $_POST['submitWord'];

  $sql = "INSERT INTO Dictionary (Word,AddDate) value( Word='".$word."',AddDate='".CURDATE()."')";
  if (mysql_query($sql)) {
    echo("<P>Your word has been added.</P>");
  } else {
    echo("<P>Error adding submitted word: " .
         mysql_error() . "</P>");
  }
}
?>

yeah gud point... bt network18 i believe instead of "value" it should be "values" in the query...

Are you sure you don need this dose?

u really feel i need that!! plz correct me if i said somthin wrong..

Are you sure you don need this dose?

Oh yes, that is the humour way of saying that you need that you need that tutorial. It is great by a popular writer of the books

Ahghh!
<sorry>
I don't meant you but the poster of thread!
It is great for beginners. I quoted a wrong person,
</Sorry>

aahhh its fine... i was starting to get worried that after spending 2 months coding, some1 s suggesting me to read that absolute beginners stuff.. :P

Ahghh!
<sorry>
I don't meant you but the poster of thread!
It is great for beginners. I quoted a wrong person,
</Sorry>

Still not working for me. I don't know the code, so I'm not sure what to look for, but I made sure that all the variable names and everything were correct.

Here's the code that I'm using:

<FORM ACTION="<?php echo($PHP_SELF); ?>" METHOD="post">
<P>Type your word here:<BR>
<TEXTAREA NAME="word" ROWS="2" COLS="40" WRAP="HARD"></TEXTAREA><BR>
<INPUT TYPE="SUBMIT" NAME="submitWord" VALUE="SUBMIT">
</FORM>

<?php
$word = $_POST['submitWord'];
if ("SUBMIT" == $submitWord) {
  $sql = "INSERT INTO Dictionary SET " .
         "Word='$word', " .
         "AddDate=CURDATE()";
  if (mysql_query($sql)) {
    echo("<P>Your word has been added.</P>");
  } else {
    echo("<P>Error adding submitted word: " .
         mysql_error() . "</P>");
  }
}
?>

If this helps, when I use PuTTY to check the contents of the database, I see this:

mysql> select * from Dictionary;
+----+----------+------+----------------------------------------------+------------+
| ID | Word     | PoS  | Definition                                   | AddDate    |
+----+----------+------+----------------------------------------------+------------+
|  2 | abstract | adj  | NULL                                         | 0000-00-00 |
|  3 | abstract | adj  | NULL                                         | 0000-00-00 |
|  4 | abstract | adj  | not concrete; hard to understand; intangible | 2009-11-08 |
+----+----------+------+----------------------------------------------+------------+
3 rows in set (0.01 sec)

Are you sure you don need this dose?

Thanks! I'll look at that now.

why dont u use the code suggested above... ur sql query syntax itself is wrong.. how do you expect to get a database entry with that...
general syntax for insert statement is-
INSERT INTO [tablename] (col1,col2 ...) VALUES (val1, val2...);

Also ur table structure shows other fields also besides word and date... are u sure when u are inserting a new row, these values are allowed to be null?

Still not working for me. I don't know the code, so I'm not sure what to look for, but I made sure that all the variable names and everything were correct.

Here's the code that I'm using:

<FORM ACTION="<?php echo($PHP_SELF); ?>" METHOD="post">
<P>Type your word here:<BR>
<TEXTAREA NAME="word" ROWS="2" COLS="40" WRAP="HARD"></TEXTAREA><BR>
<INPUT TYPE="SUBMIT" NAME="submitWord" VALUE="SUBMIT">
</FORM>

<?php
$word = $_POST['submitWord'];
if ("SUBMIT" == $submitWord) {
  $sql = "INSERT INTO Dictionary SET " .
         "Word='$word', " .
         "AddDate=CURDATE()";
  if (mysql_query($sql)) {
    echo("<P>Your word has been added.</P>");
  } else {
    echo("<P>Error adding submitted word: " .
         mysql_error() . "</P>");
  }
}
?>

If this helps, when I use PuTTY to check the contents of the database, I see this:

mysql> select * from Dictionary;
+----+----------+------+----------------------------------------------+------------+
| ID | Word     | PoS  | Definition                                   | AddDate    |
+----+----------+------+----------------------------------------------+------------+
|  2 | abstract | adj  | NULL                                         | 0000-00-00 |
|  3 | abstract | adj  | NULL                                         | 0000-00-00 |
|  4 | abstract | adj  | not concrete; hard to understand; intangible | 2009-11-08 |
+----+----------+------+----------------------------------------------+------------+
3 rows in set (0.01 sec)

Thanks! I'll look at that now.