how to save the jpg file into database using file upload control?
how to retrive that stored jpg file from database and show on image control.
i have table has two fields Id(int),imageData(image).

>how to save the jpg file into database using file upload control?

Use/learn ADO.NET classes.

>how to retrive that stored jpg file from database and show on image control.

1. Retrieve binary data from database and save into a file (say temp.gif).
2. Set ImageUrl property of Image control.

how to save the jpg file into database using file upload control?
how to retrive that stored jpg file from database and show on image control.
i have table has two fields Id(int),imageData(image).

I think saving image in database is not a good practice.finally it will slow down your database and retrieved image quality wont be good.so its always good to save image file in disk.

To upload file into server follow the below sample code:

protected void cmd_Upload_Click(object sender, EventArgs e)
    {
        string s_Image_Name = txt_Image_Name.Text.ToString();
        if (FileUpload1.PostedFile != null && FileUpload1.PostedFile.FileName != "")
        {
            byte[] n_Image_Size = new byte [FileUpload1.PostedFile.ContentLength];
            HttpPostedFile Posted_Image = FileUpload1.PostedFile;
            Posted_Image.InputStream.Read(n_Image_Size, 0, (int)FileUpload1.PostedFile.ContentLength);

            SqlConnection conn = new SqlConnection(ConfigurationManager.ConnectionStrings["TestConnection"].ConnectionString);

            SqlCommand cmd = new SqlCommand();
            cmd.CommandText = "INSERT INTO Images(Name,[Content],Size,Type)" +
                              " VALUES (@Image_Name,@Image_Content,@Image_Size,@Image_Type)";
            cmd.CommandType = CommandType.Text;
            cmd.Connection = conn;

            SqlParameter Image_Name = new SqlParameter("@Image_Name", SqlDbType.VarChar, 500);
            Image_Name.Value = txt_Image_Name.Text;
            cmd.Parameters.Add(Image_Name);

            SqlParameter Image_Content = new SqlParameter("@Image_Content", SqlDbType.Image, n_Image_Size.Length);
            Image_Content.Value = n_Image_Size;
            cmd.Parameters.Add(Image_Content);

            SqlParameter Image_Size = new SqlParameter("@Image_Size", SqlDbType.BigInt, 99999);
            Image_Size.Value = FileUpload1.PostedFile.ContentLength;
            cmd.Parameters.Add(Image_Size);

            SqlParameter Image_Type = new SqlParameter("@Image_Type", SqlDbType.VarChar, 500);
            Image_Type.Value = FileUpload1.PostedFile.ContentType;
            cmd.Parameters.Add(Image_Type);


            conn.Open();
            cmd.ExecuteNonQuery();
            conn.Close();
        }
    }

To display the image form database follow the below post:
http://shawpnendu.blogspot.com/2009/12/display-images-in-gridview-from-sql.html