Member Avatar for amit.hak50

I am getting this error ,can anyone help me :

Warning: Invalid argument supplied for foreach() in /home4/thesisth/public_html/pdfsearchmachine/classes/rss.php on line 14

Here is the rss.php

code

<meta http-equiv="Content-Type" content="text/html; charset=utf-8">          

<?
$search = $_GET["search"];
$replace = " "; $with = "+";
$search = str_replace($replace, $with, $search);

if ($rs = $rss->get("http://api.search.yahoo.com/WebSearchService/rss/webSearch.xml?appid=yahoosearchwebrss&query=originurlextension%3Apdf+$search&adult_ok=1&start=$start")) 
{

}

// Go through the list powered by the search engine listed and get the data from each <item>
$colorCount="0";

   foreach($rs['items'] as $item) 
	{ 

	// Get the title of result

	   $title = $item['title'];

	// Get the description of the result

	   $description = $item['description'];

	// Get the link eg amazon.com

	   $urllink = $item['guid'];

if($colorCount%2==0)
{
$color = ROW1_COLOR;
}
else
{
$color = ROW2_COLOR;
}

include "resulttemplate.php";
$colorCount++;
 echo "\n"; 

} 

	



?>
  • 4 Contributors
  • 7 Replies
  • 269 Views
  • 1 Day Discussion Span
  • Latest Post Latest Post by amit.hak50

Recommended Answers

All 7 Replies

Member Avatar for vibhaJ

For php error,
Always put foreach in if condition.

if(count($rs['items'])>0)
{
	foreach($rs['items'] as $item) 
	{ 
		//--- code---
	}
}
else
{
	echo 'There is no items...';
}

And for URL there are some php variables in url like $search.
Check the string generated (output of php code) in the one you have used in another site.

Member Avatar for amit.hak50

For php error,
Always put foreach in if condition.

if(count($rs['items'])>0)
{
	foreach($rs['items'] as $item) 
	{ 
		//--- code---
	}
}
else
{
	echo 'There is no items...';
}

And for URL there are some php variables in url like $search.
Check the string generated (output of php code) in the one you have used in another site.

Someone told me that maximum number of searches per day by yahoo is only 5000 ,if you want to advance that ,you need to pay..is that true?

Member Avatar for amit.hak50

For php error,
Always put foreach in if condition.

if(count($rs['items'])>0)
{
	foreach($rs['items'] as $item) 
	{ 
		//--- code---
	}
}
else
{
	echo 'There is no items...';
}

And for URL there are some php variables in url like $search.
Check the string generated (output of php code) in the one you have used in another site.

It is working with that URL ,previuos one ,I did not do any changes,Sometimes it works and sometimes don't ,I don't know why..

Member Avatar for tomato.pgn

It might be the api is not responding correctly...this problem exist sometimes due to heavy load or change(updation or modification) in api.....

Be a part of the DaniWeb community

We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.