Member Avatar for Hakoo

Hello Friends,

I have checkbox which is generated dynamically. Here the code is :

<?php	
	$i=0;
	while($row1 = mysql_fetch_array($result))
	 {?>
		<label><?php echo $i++ ?><input type="checkbox" name="chk_list[]"  value="<?php echo $row1['Veh_id'];?>" class="txt" onClick=""><?php echo $row1['Veh_nm']; ?></input></label></br>
	 		
	<?php  } 
		
		
		
		?>

Now, I want to insert IDs and related information which checkboxes are checked. So, I tried small javascript on button when its clicked.

function validate()
		{
			
			
			var chk = document.frm.chk_list;
			//alert (chk);
			for(i=0; i<chk.length; i++)
			if(chk[i].checked==true){
			alert (chk[i].value);
			}			
			
		}

now thing is how can I access this value in PHP? Is there any trick to pass array from javascript and use them in PHP code??

Thanking You,
Hakoo Desai.

  • 3 Contributors
  • 3 Replies
  • 221 Views
  • 7 Hours Discussion Span
  • Latest Post Latest Post by vibhaJ

Dani AI

Generated

The easiest, safest flow is: keep the checkboxes inside a real <form> with name="chk_list[]", submit the form (or send it with AJAX), then handle the received array on the server with validation and a prepared statement. and already pointed to submitting and looping over the posted array; below is an example that keeps those ideas but shows a modern, secure insertion approach and a minimal fetch-based submit.

Server-side: validate, cast values to integers, then use PDO prepared statements inside a transaction so a partial failure does not leave the DB inconsistent.

<?php
if (!empty($_POST['chk_list']) && is_array($_POST['chk_list'])) {
    $ids = array_map('intval', $_POST['chk_list']);         // sanitize
    $pdo = new PDO('mysql:host=localhost;dbname=your_db;charset=utf8mb4','dbuser','dbpass',
                   [PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION]);
    $pdo->beginTransaction();
    $stmt = $pdo->prepare("INSERT INTO selected_vehicles (veh_id, created_at) VALUES (:vid, NOW())");
    foreach ($ids as $vid) { $stmt->execute([':vid' => $vid]); }
    $pdo->commit();
}
?>

Client-side (optional): submit the form with fetch to keep UX snappy and still let PHP receive the same array.

document.querySelector('form').addEventListener('submit', function(e){
  e.preventDefault();
  fetch(this.action, { method: this.method || 'post', body: new FormData(this) })
    .then(res => res.text()).then(console.log).catch(console.error);
});

Practical notes and troubleshooting:

  • In ’s markup avoid using a closing </input> tag (input is self-closing). Browsers tolerate it but it is invalid HTML.
  • Ensure the checkboxes are inside the <form> and that the form method matches what PHP reads ($_POST vs $_GET).
  • Always validate/sanitize on the server (arraymap('intval', ...) above) and avoid deprecated mysql* functions; migrate to PDO or mysqli.
  • Use print_r($_POST) (as suggested) when debugging to confirm what was submitted, and log DB errors or exceptions so failures are visible.

Recommended Answers

All 3 Replies

Member Avatar for urtrivedi

if you have placed checkbox chk_list[] in the html <form> element, then you can submit the form with action=some.php.

Now in your php file
you will get array of selected values
$_POST[0]
$_POST[1]
$_POST[2]
.
.
.
.
$_POST[n]

Here n is number of selected check boxes,
Here Unselected checkboxes are not available in the array.

Member Avatar for vibhaJ

You can also use loop for getting its value.

<?
	$chk_list = $_POST['chk_list'];
	foreach($chk_list as $key=>$Veh_id)
	{
		echo '<br />'.$Veh_id.' is checked';
	}
?>
Member Avatar for vibhaJ

Add this code.
This code will print all forms posted data.

if(isset($_POST))
{
    echo '<pre>';
    print_r($_POST);
}

Post your output here.

Edited by vibhaJ because: n/a
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