0

Hi!

So I managed to upload the picture via php to a folder BUT my problem now is that I want to INSERT the location path of the uploaded picture to the user's pic_location in the database and I don't know how the query will look if I want to achieve that.

The member is logged in when he uploads the pic so the SESSION is running.

I will give you my code to have a look see and if you can spot what to do...

Thanks

My picUpload.php (Where I uploaded the picture and where I want to INSERT the location path into the user's pic_loaction column in the table users)

<?php 
	 include 'connect.php';
	 include 'header.php';
 
	 //This is the directory where images will be saved 
	 $target=$_SERVER['DOCUMENT_ROOT'] . "/images/" . basename( $_FILES['file']['name']); 
 
	 //This gets all the other information from the form 
	 $pic_location=($_FILES['file']['name']); 
 
	 //Writes the information to the database 
	 $sql = "INSERT INTO users (pic_location) VALUES ('$pic_location')" ; 
 
	 //Writes the photo to the server 
	 if(move_uploaded_file($_FILES['file']['tmp_name'], $target)) 
	 { 
 
	 //Tells you if its all ok 
	 echo "The file ". basename( $_FILES['file']['name']). " has been uploaded, and your information has been added to the directory"; 
	 } 
	 else { 
 
	 //Gives and error if its not 
	 echo "Sorry, there was a problem uploading your file."; 
	 }
 
	 ///////////////////////////////
	 ////////// HELP HERE //////////
	 ///////////////////////////////
 
	 //Putting the storage path in the logged in user's pic_location path
	 //HOW WILL THE QUERY LOOK IF I WANT TO ADD THE PATH OF THE UPLOADED PICTURE TO THE USER'S pic_location IN THE DATABASE TABLE???
 
	 $sql = "INSERT INTO
					users(pic_location)
				VALUES('" . mysql_real_escape_string($_POST['pic_location']) . "',NOW(),0)";
 
		$result = mysql_query($sql);
		if(!$result)
		{
			//something went wrong, display the error
			echo 'Error!';
		}
		else
		{
			echo 'Success!';
		}
 
?>

my profile.php

<?php
	include 'connect.php';
	include 'header.php';
 
		if(isset($_SESSION['signed_in']) == false || isset($_SESSION['user_level']) != 1 )
			{
				//the user is not an admin
				echo '<br/>';
				echo 'Sorry! You have to be <a href="/signin.php"><b>logged in</b></a> to view your profile <a href="signup.php" title="Become a registered user!"></a>.';
				echo '<br/><br/>';
			}
			else
			{
				echo '<h2>Profile of </h2>'.$_SESSION['user_name'];
				echo '<h2>Info about you: </h2>';
				echo '<img src="beetgejo.jpg"/>';	echo'<pp><a href="#" title="Change your profile picture">edit</a></pp>';
				echo '<br/><br/>';
				echo '<b>Logged in as: </b>'.$_SESSION['user_name'];	echo'<pp><a href="#" title="Change your user name">edit</a></pp>';
				echo '<br/><br/>';
				echo '<b>Your email address: </b>'.$_SESSION['user_email'];	echo'<pp><a href="#" title="Change your email address">edit</a></pp>';
				echo '<br/><br/>';
				echo '<b>Your user level: </b>'.$_SESSION['user_level'].'   (1 = admin AND 0 = user)';
				echo '<br/><br/>';
				echo '<b>Your friends: </b> // FRIENDS';
 
				//echo 'Welcome, ' . $_SESSION['user_name'] . '! <br /><br/><br/><a href="index.php"><b>Proceed to the link sharing</b></a>.';
				///////////////////////////////
				/// adding users as friends ///
				///////////////////////////////
 
				//while($user = mysql_fetch_array($result))
				//echo $user['user_name'].' 
					//<a href="addfriend.php?user='.$user['id'].'">ADD TO FRIENDS</a><br/>';
				echo 'Do you want to upload or change your profile picture?';
				echo '<br/><br/>';
				echo '<form action="picUpload.php" method="post" enctype="multipart/form-data">
						<label for="file">Filename: </label>
						<input type="file" name="file" id="file"/>		
						<br/>
						<input type="submit" name="submit" value="Upload" />
					 </form>';
 
				//NOW I WANT TO MAKE A SPECIFIC "ADD AS FRIEND" LINK NEXT TO EACH USER
 
 
			}
			include 'footer.php';
?>

and my database.sql

CREATE TABLE users (  
user_id     INT(8) NOT NULL AUTO_INCREMENT,  
user_name   VARCHAR(30) NOT NULL,  
user_pass   VARCHAR(255) NOT NULL,  
user_email  VARCHAR(255) NOT NULL,  
user_date   DATETIME NOT NULL,  
user_level  INT(8) NOT NULL,  
pic_location  VARCHAR(255) NOT NULL,  
UNIQUE INDEX user_name_unique (user_name),  
PRIMARY KEY (user_id)  
);
 
CREATE TABLE categories (  
cat_id          INT(8) NOT NULL AUTO_INCREMENT,  
cat_name        VARCHAR(255) NOT NULL,  
cat_description     VARCHAR(255) NOT NULL,  
UNIQUE INDEX cat_name_unique (cat_name),  
PRIMARY KEY (cat_id)  
);
 
CREATE TABLE topics (  
topic_id        INT(8) NOT NULL AUTO_INCREMENT,  
topic_subject       VARCHAR(255) NOT NULL,  
topic_date      DATETIME NOT NULL,  
topic_cat       INT(8) NOT NULL,  
topic_by        INT(8) NOT NULL,  
PRIMARY KEY (topic_id)  
); 
 
CREATE TABLE posts (  
post_id         INT(8) NOT NULL AUTO_INCREMENT,  
post_content        TEXT NOT NULL,  
post_date       DATETIME NOT NULL,  
post_topic      INT(8) NOT NULL,  
post_by     INT(8) NOT NULL,  
PRIMARY KEY (post_id)  
);
3
Contributors
2
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4
Views
6 Years
Discussion Span
Last Post by lps
0

get the real name with the stripslashes function
then use this

$query = "INSERT INTO table(filepath)
VALUES('$imagedir$realname')"

then you can use the a loop to get the images out.

while
<img src...../>
0

As you have the pictures uploaded to the server, I wonder why you have to input the original url. In my opinion, you should just store the name of the picture and when you load the picture, add the file location in front manually. Example:

<?php $url="http://www.example.com/img/".$url_loaded;
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