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Hi all,
I have a database which I would like to use to power an HTML list.
I'm struggling to get the loop to print out more than one line.

This is the script:

<?php
$query = "SELECT * FROM `table` ORDER BY `year` ASC";
$resultID = mysql_query($query, $conn) or die("Data not found.");
for($y = 1 ; $y < mysql_num_rows($resultID) ; $y++){
$row = mysql_fetch_assoc($resultID);
$xml_output2 = "<li id=\"";
$xml_output2 .= $row['year']."\">";
$xml_output2 .= "<img src=\"/images/".$y.".png\" width=\"256\" height=\"256\" />";
$xml_output2 .= "<h1>".$row['location']."</h1><p>".$row[…
//echo $xml_output2;
}
?>

Database connection is okay, and columns all match.
On viewing the source, one line seems to have have been pulled in correctly, but that's all.

Please help! Thanks

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Last Post by AliHurworth
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Update: Line 2 should read:

$xml_output2 .= "<h1>".$row['location']."</h1><p>".$row['event']."</p></li>";
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your count is wrong. for mysql_num_rows case where there is 1 row, this function returns 1. you have chosen in your for loop to count from 1 (which is proper) to < mysql_num_rows() which would be in this case something less than 1 think of it like one less. the loop will not even execute the body in this case, because 1<1 is false. for COUNTS of things, you should
start at 1 and use <=
OR
start at 0 and use <

most people typically do the following in place of a for like you have done (this gets all the rows and takes less code: it's an assignment within a conditional of a while loop, and it also tests for end of data):

while ($row = mysql_fetch_assoc($resultID)) {
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Thanks JMichael,
Unfortunately, still not working, and instead for 2nd row of MySQL.

<div id="display">
    	<?php
			$query = "SELECT * FROM `table` ORDER BY `year` ASC";
			$resultID = mysql_query($query, $conn) or die("Data not found.");
		    while ($row = mysql_fetch_assoc($resultID)) {
				//$row = mysql_fetch_assoc($resultID);
				$xml_output1 = "<li><a href=\"#".$row['year']."\">".$row['year']."</a></li>";
			}
			
			$query2 = "SELECT * FROM `table`ORDER BY `year` ASC";
			$resultID2 = mysql_query($query2, $conn) or die("Data not found.");
			//count rows
			$num_rows = mysql_num_rows($resultID2);
			while($row = mysql_fetch_assoc($resultID2)){
				//$row = mysql_fetch_assoc($resultID2);
				$xml_output2 = "<li id=\"";
				$xml_output2 .= $row['year']."\">";
				$xml_output2 .= "<img src=\"images/".$row['id'].".png\" width=\"256\" height=\"256\" />";
				$xml_output2 .= "<h1>".$row['location']."</h1><p>".$row['event']."</p></li>";
			}

		?>

Any more ideas - greatly appreciated

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<?php
//DB Info
// connect to db
mysql_connect("$host", "$username", "$password")or die("cannot connect server "); 
mysql_select_db("$db_name")or die("cannot select DB");

$result = mysql_query("SELECT * FROM table ORDER BY year") 
or die(mysql_error());  
while($row = mysql_fetch_array( $result )) {

$xml_output2 = "<li id=\"";
$xml_output2 .= $row['year']."\">";
$xml_output2 .= "<img src=\"/images/".$y.".png\" width=\"256\" height=\"256\" />";
$xml_output2 .= "<h1>".$row['location']."</h1><p>".$row[…
}
?>
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Codewalkz, JMichae3, thanks. Your suggestion for using while sent me back to the books, and yes it works thanks.

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