can some one help me with the below code? I am trying to create a multiple image upload form that displays the images.

I want to save the image name into my msql database and save the actual image into a folder in my dirrectory.


define('UPLOAD_PATH', $_SERVER['DOCUMENT_ROOT'] . '/upload/');
define('DISPLAY_PATH', '/upload/');
define('MAX_FILE_SIZE', 2000000);
$permitted = array('image/jpeg', 'image/pjpeg', 'image/png', 'image/gif');

if (isset($_POST['upload'])) {

$fileName = $_FILES['userfile']['name'];
$tmpName = $_FILES['userfile']['tmp_name'];
$fileSize = $_FILES['userfile']['size'];
$fileType = $_FILES['userfile']['type'];

// get the file extension 
$ext = substr(strrchr($fileName, "."), 1);
// generate the random file name
$randName = md5(rand() * time());

// image name with extension
$myfile = $randName . '.' . $ext;
// save image path
$path = UPLOAD_PATH . $myfile;

if (in_array($fileType, $permitted) && $fileSize > 0 && $fileSize <= MAX_FILE_SIZE) {
//store image to the upload directory
$result = move_uploaded_file($tmpName, $path);

if (!$result) {
echo "Error uploading image file";
} else {
$db = new mysqli("Localhost", "", "", "");

if (mysqli_connect_errno()) {
printf("Connect failed: %s<br/>", mysqli_connect_error());

$query =
 "INSERT INTO my_image(name, size, type, file_path) VALUES(?,?,?,?)";
$conn = $db->prepare($query);
if ($conn == TRUE) {
$conn->bind_param("siss", $myfile, $fileSize, $fileType, $path);
if (!$conn->execute()) {
echo 'error insert';
} else {
echo 'Success!<br/>';
echo '<img src="' . DISPLAY_PATH . $myfile . '"  height="330"  width="290"  />';
} else {
die("Error preparing Statement");
} else {
echo 'error upload file';
} else {
echo 'error';

        <title>Upload File To MySQL Database</title>
        <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1">
        <style type="text/css">
            .myc {
                font-size: 12px;
                border: 1px solid #000000;
        <form action="form23.php" 
              enctype="multipart/form-data" name="uploadform" method="post" >
          <table width="350" border="0" cellpadding="1" cellspacing="1" class="box">
                <input type="hidden" name="MAX_FILE_SIZE" value="2000000">
                <input name="userfile" type="file" id="userfile"/>
                <input name="upload" type="submit" class="myc" id="upload" value="Upload"/>

I dont want each image to have its own id in mysql database because i want to assigh four images to a user so that it can display into their profile.

I know something like this would work but please let me know if anyone knows of anything that can help.

$imageUploadDir = '../upload/';

$imageName1 = $_FILES['image1']['name'];
$tmpImageName1 = $_FILES['image1']['tmp_name'];

$imageName2 = $_FILES['image2']['name'];
$tmpImageName2 = $_FILES['image2']['tmp_name'];
$imageName3 = $_FILES['image3']['name'];
$tmpImageName3 = $_FILES['image3']['tmp_name'];
$imageName4 = $_FILES['image4']['name'];
$tmpImageName4 = $_FILES['image4']['tmp_name'];

// the files will be saved in filePath
$imagePath1 = $imageUploadDir . $imageName1;
$imagePath2 = $imageUploadDir . $imageName2;
$imagePath3 = $imageUploadDir . $imageName3;
$imagePath4 = $imageUploadDir . $imageName4;

$imageName1 = 'upload/'. $imageName1;
$imageName2 = 'upload/'. $imageName2;
$imageName3 = 'upload/'. $imageName3;
$imageName4 = 'upload/'. $imageName4;

// move the files to the specified directory
// if the upload directory is not writable or
// something else went wrong $result will be false
if( file_exists($tmp_name) ){
move_uploaded_file($tmp_name, $filePath);
if( file_exists($tmpImageName1) ){
move_uploaded_file($tmpImageName1, $imagePath1);
if( file_exists($tmpImageName2) ){
move_uploaded_file($tmpImageName2, $imagePath2);
if( file_exists($tmpImageName3) ){
move_uploaded_file($tmpImageName3, $imagePath3);
if( file_exists($tmpImageName4) ){
move_uploaded_file($tmpImageName4, $imagePath4);

$fileName = addslashes($fileName);
$filePath = addslashes($filePath);

<input name="image1" type="file" id="ufile[]" size="50" /></td>
<input name="image2" type="file" id="ufile[]" size="50" /></td>
<input name="image3" type="file" id="ufile[]" size="50" /></td>
<input name="image4" type="file" id="ufile[]" size="50" /></td>

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Anyone? please help.


the name on these form inputs...

     <input name="image1" type="file" id="ufile[]" size="50" />

should also be in an array like this

     <input name="ufile[]" type="file" id="ufile[]" size="50" />

UPDATE! I have to remove some codes, because it was deprecated...just use $_FILES..

Sorry but that doenst help much.

thanks though.

ok.. here is the php.net manual for multiple file uploads Click Here..Read on leehowarth1 post.. or by anyone should and can help you out.

We cannot use $_FILES['this'], because the upload is coming as an array. So, your codes above can be something like this

 $fileNameOne = $_FILES['ufile']['name'][0];
 $fileNameTwo = $_FILES['ufile']['name'][1];

Or better yet, just use one of the recommended approach in php.net as linked above..

I could have written this script.. this is not pretty hard to do, but I am preparing for my flight to California. I need to be in CalTech by Monday. So, I aplogize if I can't do it this time. Normally, I would write a simple demo script, but not this time.

Thank you sir. I really appreaciate it. I am at work and will look into it once i get home.

Have a safe flight.

If anyone else has anything to share please do :)

The pgp manual doesnt really explain how to save the images into the msql and server folder it seems.

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