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Member Avatar for thecameraman

Hello, I want to display the fields that were updated. When a user edits their information, example; "FIRST NAME:John LAST NAME: Stih Update to:UPDATE users SET firstname = '$firstname', lastname = '$lastname' FIRST NAME: John LAST NAME: Smith I would want it to print "You updated your Last name"

Member Avatar for pritaeas
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Member Avatar for xbat

I on my drop down boxes it keeps on selecting more than one option I just want it to select out of one row... for some reason this won't work nothing shows - $query["cost1"] = "SELECT ourprice as text, ourprice as value FROM `fruitinventory` WHERE seeddescription='%s' AND fruitdescription='%s'"; Something shows …

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Member Avatar for system_Broken

I WANT SEND ITEMS INTO DATABASE WITH ONE TIME CONNECTION OPEN ? MYCONN.OPEN(); FOR(INT I =0; I < CODE.COUNT ; I ++) { DB.SUBMITITEMS(CODE[I]); //IS IT RIGHT IF I HAVE 100 ITEMS TO SEND DATABASE WITH ONCE TIME OPEN CONNECTION OF DATABASE; OR I NEED TO REOPEN AND CLOSE CONN …

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In my desktop application whenever execute the code to backup my database from java application the app goes on waiting state may be for password , which we have to enter while backing up from command line. But i've provided the username and password of database in the code. Why …

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Dear experties, I want to display data from Mysql by keyword but my code doesn't work. Maybe you have suggestion for this environment. please...

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Member Avatar for gordey wilson

1 down vote favorite You can't vote for your own post. (click on this box to dismiss) I have a very big problem with my website. I have a form, more like a text box used in submitting comments, that not the problem. The problem is displaying the comments. I …

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trying to develop a system to assign grades to students. The system reads marks from my database, and assigns a grade after getting average of scores. Used case statements, keep throwing errors. So i tried if statements but its giving me issues. Someone know a better way to do it? …

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Member Avatar for xbat

I have a bunch of drop down boxes, then after they are selected the the total amount automatically appears at the bottom.. the only problem is it appeears like this - <span id="resp">Total</span> How would I make this insert into the database?

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Member Avatar for Ctechnology24

Help, I need a free hosting site! I have a website made of PHP that I need to upload to a web server and a VB.net application on my PC, I saw tutorials on how to connect my VB.net application to my database located in the web server with my …

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I have a GoDaddy account and I want to connect dreamweaver to the mysql server... but I keep getting errors... no matter what I do... can someone assist me? I called GoDaddy, they couldn't answer me so they blamed Dreamweaver...

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Member Avatar for dre-logics

>I use MySQL database Two tables: Table 1 articles Field: article nb article description supplier cell 100 nails company 1 no 200 screws company 2 yes >Table 1 stock Field: article nb. barcode nb. barcodedescription instock 100 10011 nails 2 inch 5000 100 10012 nails 5 inch 0 200 20012 …

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Member Avatar for spacehans

Hello, I am trying to display various types of search results on a seperate page: Here is my PHP CODE for the form: --------------------------------------------------------------------------------------------------------------- <table width="75%" cellspacing="10" cellpadding="10"> <tr> <td width="22%" class="subtiwhite"><strong>Search by Name:</strong></td> <td width="74%"><form name="form1" method="get" action="searchname.php"> <input type="text" name="namelist" id="namelist"> <input type="submit" name="searchname" id="searchname" value="Submit"> </form></td> <td …

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Member Avatar for HometownHero

I can't seem to display the image.. Here is my code.. <?php $user='root'; $server='localhost'; $db='db_gamecube';//database name mysql_connect('localhost','root'); mysql_select_db($db); $pass=$_POST['password']; $uname=$_POST['uname']; $sql="select * from tb_register where username ='$uname' and password='$pass'"; $result= mysql_query ($sql) or die (mysql_error()); if(mysql_num_rows($result)==1) { session_start(); $_SESSION['guest']=$uname; echo "<form method ='post' action='login_edit.php'>"; $records=mysql_fetch_assoc($result); echo "<table border =10> <tr> …

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Member Avatar for ashiiiish

Hi all I want to install mysql in my redhat 5. I have downloaded an rpm but its saying that MYSQL-DEVEL not found. Kindly provide me the link of all those that I need to install.

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Member Avatar for CarterLangley

Hi again guys, I am getting information from a table that I would dearly love to format using my css styles in an external css sheet. Now I am calling the sheet in the header correctly, tested that to make sure. Here is the code I am using. This generates …

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Member Avatar for gk1993

$u = mysql_real_escape_string($_POST["username"]); $p = sha1($_POST["passwd"]); $q = "SELECT * FROM profile WHERE email=`$u` AND passwd=`$p`"; $run = mysql_query($q); if(!$run){ echo mysql_error(); } this creates *Unknown column 'mymail@gmail.com' in 'where clause'* error. This code is from a tutorial and a piece of a submit-new-post php page.

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Member Avatar for winnzor

So i have this table: numb_1 | numb_2 | numb_3 ------------------------ 5 | 5 | 5 1 | 5 | 5 2 | 2 | 3 5 | 3 | 6 5 | 4 | 7 how do i find the most common value in the 3 fields? so for …

Member Avatar for winnzor
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Member Avatar for PBDeveloper

I am trying to add the information below into a Wordpress database table (specifically the wp_postmeta table). But I can't figure out how to add the ones with the same node name. The XML document is: <?xml version="1.0" encoding="UTF-8" ?> <rss version="2.0" xmlns:excerpt="http://wordpress.org/export/1.1/excerpt/" xmlns:content="http://purl.org/rss/1.0/modules/content/" xmlns:wfw="http://wellformedweb.org/CommentAPI/" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:wp="http://wordpress.org/export/1.1/" > <channel> <title>Title</title> …

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Member Avatar for Stardemos

Hello. I'm new to php and sql. I nee to insert data in multiple tables and rows. the problem, in the first table, I just nedd 1 row, and that's fine, in the scond i need to input data in the minimum of 1 row and max of 6 row's. …

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Member Avatar for rjony321

Hi, I have login logout problem.when i LOGED IN i want my login button change it logout.But its not beahave like this.here is my code please see and help with neccessary steps: <?php if(isset($_SESSION['user_active_status'])=='1') { ?> <div class="user_purpose"> <ul> <a href="index.php?page_select=page_logout124" style=" font-family: calibri; color: white;"><li class="user_log">Logout</li></a> // page_select : …

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Member Avatar for anujthefuhrer

how date is implemented as a datatype in database in mysql(or in any other database): its representation and operations

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Member Avatar for da(code)da

i have a list and mysql table. my goal is to make the links active if there is a game in its section: this is my code: mysql_select_db("my_db", $con); $result = mysql_query("SELECT * FROM gameChart"); $row = mysql_fetch_array($result); echo "<dl><dt>Writer's Forge</dt>"; if (!$row["secID"] == 1){ echo "<dd>Collaborated Poetry</dd>";} else { …

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Member Avatar for da(code)da

Im getting a "Unknown database 'user_admin'" error and i dont see it here is my code $username = mysql_real_escape_string($_POST["Username"]); $query = "SELECT * FROM user WHERE UserName='$username'"; $result = mysql_query($query); if(mysql_affected_rows() == 0) { //All Checks Out: Create Databases $dbase = "user_" . $_POST["Username"]; mysql_query("CREATE DATABASE $dbase",$con) or die(mysql_error()); mysql_select_db($dbase, …

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Member Avatar for asaidi

Hi > nice to be in DANIWEB > really i m stucked in collecting value from ajax > i have an html select option on onchange on account i have the list of the customers belongs to the account > the problem i cannot collect the value of customer choosen …

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Member Avatar for arctushar

Hi I have a form with textarea. when user submit content through this text area. indent and paragraph is preserving in mysql. Even when I copy data from mysql via phpmyadmin, it also preserving indent and paragraph. But problem is that, when I get data from mysql via php script. …

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Member Avatar for Ebiso

I am trying to create a search form for my database where a user can search for a customer name and all of that customers addresses will be displayed. my structure looks like this Customer table + ID + First Name - Last name - Company Name Address Table + …

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Member Avatar for m.zheee

how do i create a trigger to display the columns of the record after it is inserted into the table. how do integrate php and mysql to do so?

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Member Avatar for Ctechnology24

I want to make a local application connected to the web server using vb.net also the database in webserver is connected to a PHP website, how can I decode a password(encrypted using bcrypt of PHP) using vb.net and vice versa

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Member Avatar for senergy

hi, I have trouble with getting info from my table, this is my code: [code]#include "stdafx.h" #include <iostream> #include <mysql++.h> #include <manip.h> using namespace std; #define HOST "" #define USER "senergy" #define PASSWORD "" #define DATABASE "" #define PORT 3306 // deleted info :) int main(int argc, char *argv[]) { …

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Member Avatar for sankster

$connection = mysql_connect($db_host, $db_user, $db_password) or die("error with connection"); mysql_select_db($db_name, $connection); $file=fopen("daily_user_summary.txt","r"); while (!feof($file_handle) ) { $line_of_text = fgets($file); $parts = explode(' ', $line_of_text); print $parts[0]. $parts[1]. $parts[2] . $parts[3]. "<BR>"; $query = ("SELECT name, newcredit, sum(total), team FROM tb1 WHERE NAME = '$parts[0]' and TEAM = '$parts[3]'"); $row = …

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Member Avatar for rpv_sen

Hi Friends i like to know more about the difference between mysql, Phpmyadmin, sql and also which one is more safe and secure for webpage. Can any one help me to know about it.

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Member Avatar for marky101

dim x as integer = 0 str = "SELECT uname, full_name FROM EMPLOYEE" cmd = New MySqlCommand(str, cn) ds = New DataSet da = New MySqlDataAdapter(str, cn) da.Fill(ds, "employee") Dim uname As String = ds.Tables(0).Rows(0)("uname").ToString Dim emp_name As String = ds.Tables(0).Rows(0)("full_name").ToString While x <= ds.Tables(0).Rows.Count If ds.Tables(0).Rows.Count <> 0 Then …

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Member Avatar for eLaunty9487

hello, i have a dropdown list of several values, now i am successfully created a script in which data is display from database by selecting a value from drop down i.e a post value thrown by select a value from drop down. My question is how to display data for …

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Member Avatar for gilgil2

Hi am trying to delete a row from a mysql database and can't work out why it is not working. Here is the code $link = mysql_connect('', '', '') or die('Could not connect: ' . mysql_error()); mysql_select_db('') or die(mysql_error()); mysql_query("DELETE FROM gigs WHERE gigname='".$name."'"); mysql_close($link); The $link is working, and …

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Member Avatar for mzeewashooo

i am using asp.net on vb 2010 to build a website. my database is mysql. iam trying to add a new data source, when i select mysql, then i enter the name of the server, it closes the window by it self. then it tell me that .net framework data …

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Member Avatar for mzeewashooo

iam creating an online customer ordering system, and i will want to connect to a mysql dtabase that i have created.

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Member Avatar for SagarSe7en

Hey Friends, I recently came across a question which asks to approximate the data volume of a table which contains 10 Million records. Any idea on how to do it? Thanking You In Advance.

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Member Avatar for phpDave

Hi, I trying to user 3 AND operators in one Select Statement. It's not working. Is this even posable. If not, any suggestions? Here is the code: $query_Recordset1 = "SELECT * FROM user JOIN message WHERE message.user2 = '$user2' AND message.user_id = '$user2' AND email = '$email'"; Thanks!

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Member Avatar for fabzster

Hi I use the following Query: SELECT DISTINCT COUNT(tblpolicies.PolicyNumber)AS Figures, tblstores.GroupName, tblstores.StoreName, tblstores.StoreType FROM tblpolicies, tblstores WHERE DateReceived BETWEEN '2012-06-01' AND '2012-06-30' AND tblstores.StoreType='FLAGSHIP' AND tblpolicies.PolicyStatus='ACTIVE' AND tblstores.StoreStatus='ACTIVE' AND tblpolicies.StoreId=tblstores.StoreId GROUP BY StoreName ORDER BY Figures DESC What this does is give me a result: 95 GroupName StoreName StoreType This …

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Member Avatar for Sabyre

OMG Optimization.... One of those things that is widely discussed but with no real specifics because everyones setup and situation is different. So I spent all day trying to find ways to accomplish this as our SQL server was maxed out. Let me do a bit of setup explination.... We …

Member Avatar for smantscheff
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Member Avatar for muralibobby2015

hello, our site have 1000 users.here i have to give unique numbers from '000' to '999' to each user. now i am adding from starting '000'. how can i give unique numbers to users when adding and updating users? Thanks

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Member Avatar for aianne

Hello everyone! I am a student and I am currently working for online voting system for my school. I am having a hard time how to prevent users/students from multiple votes. Could please give me some example that users can only vote once using their ID number? I have a …

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566
Member Avatar for selfmastery

I am running easyphp12 running mysql as a local db server for a some software. This software can also connect to a remote db where it doesnt give this error while performing the exact mysql query, so I only get the error when using the local db. Ive tried increasing …

Member Avatar for smantscheff
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484
Member Avatar for cubalibras

Hello all, I'm trying to set up an add contacts page but when I click submit then check the database there is nothing there. I ran my sql query in phpMyadmin and got an error but for the life of me I cannot figure out what is wrong. I can …

Member Avatar for scaiferw
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Member Avatar for madhu123456789

I have created admin panel with admin having rights to create users now i want to give user privileges through admin to view selected columns in mysql table.How can i do that code in php?

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Member Avatar for ak47carbon

i have 'topic' and 'comment' fields in table of database ,when some one give comment on topic no 1 ,it save in dabase with topic number and comment, i want show topic number with higest comment. tell me sql query to show result

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Member Avatar for Djmann1013

Hi. I am having trouble with this: <?php $host="localhost"; // Host name $username="username"; // Mysql username $password="password"; // Mysql password $db_name="database"; // Database name $tbl_name="table"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); // Line with the error (Line 8) mysql_select_db("$db_name")or die("Error. MySQL …

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Member Avatar for ganges

employee_list.jsp <%@ page language="java" contentType="text/html; charset=ISO-8859-1" pageEncoding="ISO-8859-1"%> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <HTML> <HEAD><TITLE>Employee List</TITLE></HEAD> <BODY> <%@ page import="java.sql.*" %> <%@ page import="java.lang.ClassNotFoundException" %> <% Statement st = null; ResultSet rs = null; Connection conn = null; try { Class.forName("com.mysql.jdbc.Driver"); conn = DriverManager.getConnection("jdbc:mysql://localhost:3306/"+"Hibernate MySQL","root","root"); st = conn.createStatement(); …

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Member Avatar for Shizuo

How do I change all greater than .00 cents to .49 cents be .00 and all greater than .50 to be round off? I'm using SqlYog btw. Example: price 1: 16:03 price 2: 16:53 Output: price 1: 16:00 price 2: 17:00

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Member Avatar for Djmann1013

Hi I am having trouble with this code: <? $host="mysql6.000webhost.com"; // Host name $username="removed"; // Mysql username $password="removed"; // Mysql password $db_name="removed"; // Database name $tbl_name="direct"; // Table name // Connect to server and select database. mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("Error. MySQL Not Responding."); $SQL = "SELECT * …

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The End.