39,393 Topics
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| | I want to create view on my database on free hosting website. I am unable to create views same query if I run on my localhost then it creates view. Is due to some limitation which is causing not to create views on free hosting website  |
| | Hi I purchased windows hosting for php from Godaddy. But my .htaccess is not support in windows, so i have to use web.config for my redirection and hidding the filename extension. Can anyone please help me to fix the issue. |
| | hello everyone, i had to make a new system for practicum student system this is coding for view student that has been registered. first of all sorry fpr the keywprd that you dont understand cause i am Malaysian `<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta …  |
 | With following code I tried to upload image and video file at the same time but, image file is uploading & video file is not uploading <form class="pure-form pure-form-aligned" action="Processor.php" method="post" enctype="multipart/form-data" > <fieldset> <div class="pure-control-group"> <label for="image">Upload image</label> <input type="file" name="image" class="pure-input-1-4" /> </div> <div class="pure-control-group"> <label for="video">Upload video</label> …  |
 | Hello, I want to check whether one given date range is falling under another range or not. Is there function for this? Because when I am calculating this using To and FROM dates , it is taking efficient. I have to apply separate condition for TO date and FROM date. …  |
| | i want to create a image gallery,i want to insert multiple files at a time,that should be stored in a database,and i want to display that in my profile.php as a gallery. |
| | Hi. I am displaying image dynamically from database, When I click the particular image I want to show that image in a popup or lightbox in a simple way. How to do? |
| | Hello, i'm having a little bit of an issue with a portion of code ... It's for a portfolio gallery. $sliders_out = '<div class="fx"><ul class="slides">'; foreach($slides as $slide) { $local = substr(str_replace(array(get_bloginfo('url'), '.jpg', '.png'), array('.', '', ''), $slide['slide_image']), 2); $locals = array_merge(glob($local.'*1024*'), glob($local.'*768*'), glob($local.'*')); rsort($locals); if (isset($locals[0])) $src = $locals[0]; … |
 | Guys what is wrong with my code? Why it gives me an output "hi"! Can you explain it to me. Please. Thank You! <?php $a = "Unemployed"; if ($a == "Employed, Locally" or "Employed, Abroad"){ echo "hi"; } elseif ($a == "Unemployed"){ echo "hello"; } ?> |
| | Hi everyone, I am still quite new to HTML and PHP. I have a form in HTML pointing to a PHP script that sends an email. But it doesn't work - please tell me where I am going wrong! The HTML is: <div class="main-content three-fourths"> <h1>Get in touch</h1> <p class="lead">We'd …  |
| | [home page](http://pastebin.com/DHWcW3aU) [css sheet](http://pastebin.com/LFgnjXkt) can u tell me which is mistake i did ? |
| | Hi guys I'm using the script `add_address.php` to output a list of email addresses from the `message` box to allowed me to split the email addresses to add to each comma. I want to output the email addresses from the `message` box to the `text` box in the `send.php` script … |
| | I am looking for a script which will allow me to place a vbulletin login box on a non vbulletin page. There are couple of scripts, but they are for older versions. I am using v3.6.8 Does anyone know where to find one for 3.6.8? The closest I could find … |
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| | I have a PostMapper class like the one in http://www.sitepoint.com/integrating-the-data-mappers/ But, I modified the find method, so it can have more parameters (I want to paginate the data, so I added the limit parameter) public function find(array $columns = array('*'), array $where = array(), $offset=0, $limit=5, $orderBy=null) { $sql = … |
| | my index page <script type="text/javascript"> $(document).ready(function(){ $("#first_name").blur(function() { var first_name = $('#first_name').val(); var fathermobile = $('#fathermobile').val(); if(first_name=="") { $("#disp").html(""); } else { $.ajax({ type: "POST", url: "detail.php", data: 'first_name='+ first_name +'fathermobile='+fathermobile, success: function(html){ $("#disp").html(html); } }); return false; } }); }); and my detail.php <?php include("include/connect.php"); if(isset($_POST['first_name']) && isset($_POST['fathermobile']) ) … |
| | Warning: require_once(EzOptions.php): failed to open stream: No such file or directory in /home/u206897974/public_html/wp-content/plugins/easy-adsense-lite/easy-adsense-lite.php on line 38 Fatal error: require_once(): Failed opening required 'EzOptions.php' (include_path='.:/usr/lib/php') in /home/u206897974/public_html/wp-content/plugins/easy-adsense-lite/easy-adsense-lite.php on line 38 |
| | Hi, I don't know if there is some name for this but what I want to create a script in php which runs in the background and capable of sending and receiving messages. This is what I want to do exactly: 1. Listen to a URL http://site1.com through xmpp protocol. …  |
| | <?php session_start(); <?php session_start(); require('connect.php'); if(isset($_SESSION['username'])) { $dir="image/"; $file_name=$dir.basename($_FILES['uploads']['name']); $fileUpload=1; $imageType=pathinfo($file_name,PATHINFO_EXTENSION); $image= addslashes(file_get_contents($_FILES['uploads']['tmp_name'])); $image_name = addslashes($_FILES['uploads']['name']); $image_size = getimagesize($_FILES['uploads']['tmp_name']); if(move_uploaded_file($_FILES['uploads']['tmp_name'], $file_name)) { echo "uploaded succesfully" ; echo "<img src='$file_name' width='50px' height='50px'>"; $querry="SELECT image FROM users WHERE username='$username'" or die(mysql_error()); $result=mysql_query($querry) or die(mysql_error()); $row=mysql_fetch_assoc($result) or die(mysql_error()); $oldimage=$row['image']; unlink('directory/image/'.$oldimage); /* $deleter = … |
| | This is my code $result = msqli_query($this->db,$sql1) or die(mysqli_connect_errno()."Data cannot inserted"); this is the error message Parse error: syntax error, unexpected '$result' (T_VARIABLE) in C:\xampp\htdocs\project\class.user.php on line 25 |
 | Hi, I have problem , the same number of comments that appears in all items this is my code : <?php $requete = $bdd->query('SELECT COUNT(c.id_commentaire) AS total FROM commentaire c INNER JOIN pytho_blog a ON a.id = c.id_article '); while($data=$requete->fetch()) { echo $data['total']; } ?> Thank you for your help … |
| | <?php $host = 'localhost'; $user = 'root'; $pass = '******'; $db = 'test'; $error = 'Error Connecting to database'; $error1 = 'Error Selecting to database'; $connect = mysql_connect($host,$user,$pass) or die($error); $select_db = mysql_select_db($db) or die($error1); ?> <table border="1px"> <tr> <div class="differentLine"> <th > </th> <th > 9:15 - 10:15 </th> <th … |
| | I need to read the span value and insert into database in php <span class="GrandTotal">0.00</span>  |
| | Hey Im making an online store and cant figure out the section on inserting data into a table (in this case its inserting customer details into a customer table). Its the VALUES line that is displaying the error: mysql_query() expects parameter 1 to be string, resource given. I have looked …  |
 | Hi im getting this error on inobox.php any ideas please Warning: implode(): Invalid arguments passed in /home/jktempla/public_html/SCRIPTS/DATINGSCRIPT/inbox.php on line 199 <?php // Fetch user random for display on bottom <THIS LINE>$idtopuid = implode(',', $topuid);<THIS LINE> <THIS> $userquery = mysql_query("select * from user where user_id != '".$_SESSION['userid']."' and user_id NOT IN … |
| | Hi guys! I have a database which holds a table called users. in there i have a balance column which contains a numeric value. I have the following code and for some reason it doesnt work: <?php session_start(); include_once("config.php"); ?> <!DOCTYPE html> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Search</title> … |
 | hy im using this script but unf cant find the bug related to update the values, its keep telling succesuful update but dsnt update in db...[Click Here](http://www.script-tutorials.com/datatables-data-from-ajax-edit-in-place/) |
 | Hello pals. I have a code here that is updating only the last column of my sql database table. how can I upgrade it to work for the rest upper rows please. my code is as follows <?php error_reporting (0); // Connect to server and select databse. $mysql_hostname = "localhost"; … |
| | Hi , In a form , I have a field for image , in edit page, i can display that image, when I am clicking update, without modifying image it shows error in image. How to save previous image if its not changed. Sample Code: <span><img src="profile/<?=$rows["upload"]; ?>" id="blah" style="height:25%; … |
| | My Model : admin_login_model.php Unable to view them in browser as shown in the image below http://i.stack.imgur.com/fychj.png i am working on CodeIgniter version 3 Can anyone tell me what is the issue if ($email === $admin_email && $password = $password) { echo 'credential match'; $this->load->helper('cookie'); if ($remember_me == '1') { … |
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