Hello to all, Please some help with this. I'm newbie to XML, XLS, Xpath, etc. How can I set correctly the reference in the command "for-each select" to avoid issues with this Top node that has namespace? I'm trying to get a XLS stylesheet to get some values. The issue is that the Top node has a colon ":" in its name "doc-master:DOCMASTER1". Searching I've seen that this is named namespaces, where the prefix is doc-master and the local name is DOCMASTER1. To begin practice with something simple I'm trying to get values for BicCode and URMs that are children …

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Hello, I have got [this](http://www.yasinuludag.com/darkorange.stylesheet) a Qt stylesheet, how do I load it to my PyQt module after creating a QString Object. if I do from PyQt4 import QtCore s = QtCore.QString('c:\myProject\darkFantasy.stylesheet') the above code loads the path string rather than the actual stylesheet. So how do I load the actual content of the stylesheet file..?

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Hi, I'm having an issue with viewing an extracted document from FTP. When I try to view the document in IE I receive the following message: The XML page cannot be displayed Cannot view XML input using XSL style sheet. Please correct the error and then click the Refresh button, or try again later. -------------------------------------------------------------------------------- System error: -2146697211. Error processing resource 'file:///H:/resources/protocol.xsl'. Could it be a server issue?? I'm new to this. Thanks

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The issue I'm having is that I need to add a second stylesheet to my web site. But I'd rather not update the 20+ HTML pages with a <link href="" /> code. Is there any way to link from the existing stylesheet to another? That way I only change one page? The second stylesheet is a font from Google Fonts. Any help would be great!

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I'm a PHP newbie, and I need to replace my current code for linking to a stylesheet (which looks like `<link rel="stylesheet" href="/style.css" type="text/css"> `) by a PHP alternative. If it's important, the code I'm using which will link to it is [php-mobile detect](http://code.google.com/p/php-mobile-detect/). The structure I wanted to use was <?php include("Mobile_Detect.php"); $detect = new Mobile_Detect(); if($detect->isiOS()){ // code to run for the Apple iOS platform. <link rel="stylesheet" type="text/css" href="style.css" />; } ?> which should work, except, 1. Dreamweaver gives me a syntax error alert at the second line, and 2. I get a browser error citing an unexpected …

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Hello everyone, I'm _very_ new to xml, especially converting using an xslt. Here's my source XML generated by Eeye Retina. This data is being used by MS Access and I don't need all the data from the original XML. When I try to run the MS Access app I get an import error saying there was an error loading the transform file. A name contained an invalid character. The basic tree of the original XML is: [ICODE] ScanJob hosts host1 host1 detail 1 host1 detail 2 host1 detail X audit1 audit1 detail 1 audit1 detail 2 audit1 detail X auditN …

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Okay, so either i'm a complete idiot or i have the right to be fully irritated. I've designed a website that runs perfectly on my local machine and internal test servers in IE and FF but when i uploaded it to our live server FF stopped reading the style sheet. It still works perfectly in IE, Chrome, Safari and Opera. This is the strangest thing that has ever happened to me. I tried to google my problem and i see that people keep on mentioning the text type but in my case it is correct. it is text/css so i …

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The End.