Posts by nav33n

Interesting indeed !

<form method="post" action="resumeinsert.php" >

There is no enctype in your form. You need enctype when you are using input type=file.

$html = implode('', file($url_to_fetch)); // this is the code that gets the code fron that url into an array..

It won't gets the code from the url into an array. Try

$html=htmlentities(implode("",file("http://www.daniweb.com")));

$html will have the contents(javascript,css,..) of www.daniweb.com as a string.

What do you mean by not working ? are you getting any error ?

oops i didnt notice the extra 0 there.

Dude! you noticed an extra 0 there :P

Btw, Congrats ShawnCplus!

Waz up Just a beginner! Welcome to Daniweb! :)

As Ryan_vietnow has already suggested, uploading a file to the database is not a good idea. Upload it to the filesystem and save the path in the database. Check this link. Uploading a file is pretty simple.

However, I should notice that I have added $framePage to the included pages, other wise, I have an error : Undefined framePage variable

The 'error' you are getting is not an error but a notice. If you have turned on notices in your error_reporting, you will get these kinda notices.

Something is in the works regarding this but those of you without access to Area 51 will have to wait and be surprised.

Wow! I can't wait to be surprised :P

:icon_smile: Cheers man !

time
table
belt

Computer

sailed

Nobody Observes Old Brave Soldiers.

You are welcome :)

-659

Bed of roses is something I wish to sleep on.

If you have root password, login with ur root account, create or grant privileges to a user. Check mysql manual for more information !

Grant privileges (using root account) to the user pma. I don't think pma have sufficient privileges.

wind
now
down

Investigate

:) yes sure!

Welcome to Daniweb Imelda!

print out the query, execute it in mysql or phpmyadmin. I think $cps and $lps are not passed correctly OR the values of $cps and $lps doesn't return anything when you limit.

eg.

if(1!=2){
         include "error.php";
} else {
 include "includes/function.php";
include "includes/anotherpage.php";
........
}

The basic idea is, if(1!=2) will always return true. So, it will include error.php (where you can have a message saying the site is down or something). Make required changes in the path of all other include files and then remove the condition 1!=2.

Check where include directory is. If you are executing a script in, say for example, www/site/test/1.php and you are trying to include a file eg. functions.php, which is in www/site/include folder, you should give, include ("../include/functions.php"); because that's where the file is. If you give, include ("include/functions.php"); it wont be able to find it, hence, you get this error.

motive
mole
live

Jupiter

:) Its not a good option to have spaces in your column names btw.

check if you are echoing anything or having any html tags before calling a header function.

Damn.. ok.. Try this.. Update only a part of the query. For example, update only 1 field first. If it doesn't give you any error, try 2 fields. Keep doing it until you get the error. Then you will know what is causing the error.

While listing the records, show previous name in a textbox and when submit is clicked, update it ?

-655

start and end are keywords. Try changing your column names to something else.

yep! once in a while! ;)

Mild seven

Ferrari or Mc laren ?

:) you have the insert statements outside the loop.
Put

//process form
 
      //this is your add query....
  
      $name = $_POST['name'];
 
      $email = $_POST['email'];
 
      $contact = $_POST['contact'];
 
      $person_attend = $_POST['person_attend'];
  
      $comment = $_POST['comment'];
 
      $query = "INSERT INTO rsvp (id, name, email, contact, person_attend, comment)
   
      VALUES ('', '$name', '$email', '$contact', '$person_attend', '$comment')";
      
      $results = mysql_query($query) or die
  
      ("Could not execute query : $query." . mysql_error());
    
      {
 
      echo "thanks you ";
 
      }
   
      mysql_close();
 }

in place of //insert statements

-652

so
sis
sos

Snippet

Fish (not to eat!)

cigar or cigarette

only insert if these fields are not null.

if($name !="" && $email!="" && $contact!="" && other variables not equal to null ){
//insert statements
} else {
//error message
}

Thats because you dont have a condition in your update query.

update bridal_songs set artist='someone';
update bridal_songs set track='something';

would update all the artists with 'someone' and all the tracks with 'something'. Have some condition like,

update bridal_songs set artist='someone' where id='1';
update bridal_songs set track='something' where id='1';

http://www.google.co.in/search?q=why+penguin+is+the+logo+of+linux&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a

-649

Check whether errors[0] is not equal to null or empty. If its null or empty, then query the database. If its not null, then there is some error !

:) If you think its solved, mark it as solved.

-647

ant
mat
toy

Calculator

"SELECT *
FROM `table3`
WHERE name LIKE '%hilgard\'s%"

Oh right ! I think I need to sleep for some more time! ;)

hmm.. weird.. Did you try the other option ? escaping ' ?

I am glad I m not a 'junky' ;)

Welcome :)

Welcome to Daniweb :)