error

Question

jinchiruki 0 Newbie Poster

16 Years Ago

can sumebody tell me whats wrong whis this code??
tried many times but still parse error..on line 53

and if i put validation on php,do i need to put the command at server side???
tq

<table width="1000" height="95" border="1">
  <tr>
    <td bgcolor="#0000FF">&nbsp;</td>
  </tr>
</table>



<?
   include("connect.php"); 
      //this is your validation in the form,put it here....
    { if (empty($_POST['name']))
      { 
      $errors[] = 'Please enter a name';
      }
      if (empty($_POST['email']))
      {
      $errors[] = 'Please enter an e-mail';
      }
      else if (!eregi("^[_a-z0-9-]+(.[_a-z0-9-]+)*@[a-z0-9-]+(.[a-z0-9-]+)*(.[a-z]{2,3})$", 
      $_POST['email']))
      {
      $errors[] = 'Please enter a valid e-mail address';
      }
      if (empty($_POST['contact']))
      {
      $errors[] = 'Please enter a contact';
      }
      else if (!is_numeric($_POST['contact']))
      {
      $errors[] = 'Please enter a valid contact with a numeric value';
      }
      if (empty($_POST['person_attend']))
      {
      $errors[] = 'Please enter some word';
      }
      else if (strlen ($_POST['person_attend']) > 255)
      {
      $errors[] = 'gogogogo';
   }
      if (empty($_POST['comment']))
      {
      $errors[] = 'Please enter some comment';
      }
      else if (strlen ($_POST['comment']) > 255)
      {
      $errors[] = 'comment ';
 }
      if (count($errors) > 0)
 
      {
      die(echo($errors)[0] );
      }
   
      else
 { echo "huhuhuhuh"; }
 
      //process form
 
      //this is your add query....
  
      $name = $_POST['name'];
 
      $email = $_POST['email'];
 
      $contact = $_POST['contact'];
 
      $person_attend = $_POST['person_attend'];
  
      $comment = $_POST['comment'];
 
      $query = "INSERT INTO rsvp (id, name, email, contact, person_attend, comment)
   
      VALUES ('', '$name', '$email', '$contact', '$person_attend', '$comment')";
      
      $results = mysql_query($query) or die
  
      ("Could not execute query : $query." . mysql_error());
    
      {
 
      echo "thanks you ";
 
      }
   
      mysql_close();
 }
      

?>

<br>
<a href="Index.php">View list attend</a>

php

3 Contributors
17 Replies
102 Views
1 Day Discussion Span
Latest Post 16 Years Ago Latest Post by nav33n

All 17 Replies

nav33n 472 Purple hazed!

16 Years Ago

What's the complete error ? And what do you mean by command at server side ?

johnsquibb 3 Junior Poster in Training

16 Years Ago

on line 53 you say:

die(echo($errors)[0] );

to take care of the parse error you can change this to :

die($errors[0]);

however, that will only print the first error. If you want to print all of the errors, try changing this:

if (count($errors) > 0)
{
	die(echo($errors)[0] );
}

to this:

if($errors)
{
	foreach($errors as $val)
	{
		echo "ERROR: $val <br/>"; 
	}
}

nav33n 472 Purple hazed!

16 Years Ago

There is nothing on line 51. Can you post your latest code (with CODE tags) ?

Edited 11 Years Ago by happygeek because: fixed formatting

nav33n 472 Purple hazed!

16 Years Ago

Okay! notice is not an error. You can disable the notice by changing few lines in your php.ini file. Search for error_reporting and replace it with this. error_reporting = E_ALL & ~E_NOTICE & ~E_STRICT line from your php.ini file to disable notices. Anyway, try using if(isset($errors)){ instead of if($errors){ .

nav33n 472 Purple hazed!

16 Years Ago

:) If you think its solved, mark it as solved.

Reply to this topic

Be a part of the DaniWeb community

We're a friendly, industry-focused community of developers, IT pros, digital marketers, and technology enthusiasts meeting, networking, learning, and sharing knowledge.

jinchiruki 0 Newbie Poster · Answer 1 · 2008-02-14T07:06:40+00:00

jinchiruki 0 Newbie Poster

16 Years Ago

problem solve.arigato pals

jinchiruki 0 Newbie Poster · Answer 2 · 2008-02-14T08:32:51+00:00

the validation settled..but new error comeout...

Notice: Undefined variable: errors in c:\program files\easyphp1-8\www\rsvp\added.php on line 51

jinchiruki 0 Newbie Poster · Answer 3 · 2008-02-14T09:27:31+00:00

<table width="1000" height="95" border="1">
  <tr>
    <td bgcolor="#0000FF">&nbsp;</td>
  </tr>
</table>

<center>

<?
   include("connect.php"); 
      //this is your validation in the form,put it here....
    { if (empty($_POST['name']))
      { 
      $errors[] = 'Please enter a name';
      }
      if (empty($_POST['email']))
      {
      $errors[] = 'Please enter a valid e-mail address';
      }
      else if (!eregi("^[_a-z0-9-]+(.[_a-z0-9-]+)*@[a-z0-9-]+(.[a-z0-9-]+)*(.[a-z]{2,3})$", 
      $_POST['email']))
      {
      $errors[] = 'Please enter a valid e-mail address';
      }
      if (empty($_POST['contact']))
      {
      $errors[] = 'Please enter a valid contact with numeric value';
      }
      else if (!is_numeric($_POST['contact']))
      {
      $errors[] = 'Please enter a valid contact with a numeric value';
      }
      if (empty($_POST['person_attend']))
      {
      $errors[] = 'Please enter some word for person attend';
      }
      else if (strlen ($_POST['person_attend']) > 255)
      {
      $errors[] = 'person_attend';
   }
      if (empty($_POST['comment']))
      {
      $errors[] = 'Please enter some comment';
      }
      else if (strlen ($_POST['comment']) > 255)
      {
      $errors[] = 'comment ';
  
 }
      if($errors)
{
	foreach($errors as $val)
	{
		echo "ERROR: $val <br/>"; 
	}
}
 
      //process form
 
      //this is your add query....
  
      $name = $_POST['name'];
 
      $email = $_POST['email'];
 
      $contact = $_POST['contact'];
 
      $person_attend = $_POST['person_attend'];
  
      $comment = $_POST['comment'];
 
      $query = "INSERT INTO rsvp (id, name, email, contact, person_attend, comment)
   
      VALUES ('', '$name', '$email', '$contact', '$person_attend', '$comment')";
      
      $results = mysql_query($query) or die
  
      ("Could not execute query : $query." . mysql_error());
    
      {
 
      echo "thanks you ";
 
      }
   
      mysql_close();
 }
      

?>
</center>
<br>
<a href="Index.php">View list attend</a>

jinchiruki 0 Newbie Poster · Answer 4 · 2008-02-14T09:56:59+00:00

i think it solve already..shold i mark as solve cos i not sure yet..but its working..the validation,the input data query to database...and its come out like what i key in

jinchiruki 0 Newbie Poster · Answer 5 · 2008-02-14T10:21:12+00:00

hehehe..i think i faced 1 more problem...the form,if i didnt fill it up then click submit,its prompt to key in data to form and it query to database too.how to solve??

nav33n 472 Purple hazed! Team Colleague Featured Poster · Answer 6 · 2008-02-14T11:00:13+00:00

Check whether errors[0] is not equal to null or empty. If its null or empty, then query the database. If its not null, then there is some error !

jinchiruki 0 Newbie Poster · Answer 7 · 2008-02-14T13:17:54+00:00

how??? this is mycode.

//this is your add query....
  
      $name = $_POST['name'];
 
      $email = $_POST['email'];
 
      $contact = $_POST['contact'];
 
      $person_attend = $_POST['person_attend'];
  
      $comment = $_POST['comment'];
 
      $query = "INSERT INTO rsvp (id, name, email, contact, person_attend, comment)
   
      VALUES ('', '$name', '$email', '$contact', '$person_attend', '$comment')";
      
      $results = mysql_query($query) or die
  
      ("Could not execute query : $query." . mysql_error());
    
      {
 
      echo "thanks you ";
 
      }
   
      mysql_close();
 }

nav33n 472 Purple hazed! Team Colleague Featured Poster · Answer 8 · 2008-02-14T13:26:41+00:00

if($name !="" && $email!="" && $contact!="" && other variables not equal to null ){
//insert statements
} else {
//error message
}

jinchiruki 0 Newbie Poster · Answer 9 · 2008-02-14T13:40:35+00:00

jinchiruki 0 Newbie Poster

16 Years Ago

where to flash it??

nav33n 472 Purple hazed! Team Colleague Featured Poster · Answer 10 · 2008-02-14T13:43:11+00:00

nav33n 472 Purple hazed!

16 Years Ago

only insert if these fields are not null.

jinchiruki 0 Newbie Poster · Answer 11 · 2008-02-14T14:02:22+00:00

<table width="1000" height="95" border="1">
  <tr>
    <td bgcolor="#0000FF">&nbsp;</td>
  </tr>
</table>

<center>

<?
   include("connect.php"); 
      //this is your validation in the form,put it here....
    { if (empty($_POST['name']))
      { 
      $errors[] = 'Please enter a name';
      }
      if (empty($_POST['email']))
      {
      $errors[] = 'Please enter a valid e-mail address';
      }
      else if (!eregi("^[_a-z0-9-]+(.[_a-z0-9-]+)*@[a-z0-9-]+(.[a-z0-9-]+)*(.[a-z]{2,3})$", 
      $_POST['email']))
      {
      $errors[] = 'Please enter a valid e-mail address';
      }
      if (empty($_POST['contact']))
      {
      $errors[] = 'Please enter a valid contact with numeric value';
      }
      else if (!is_numeric($_POST['contact']))
      {
      $errors[] = 'Please enter a valid contact with a numeric value';
      }
      
      
      if (empty($_POST['person_attend']))
      {
      $errors[] = 'Please enter some word for person attend';
      }
      
      
      else if (strlen ($_POST['person_attend']) > 255)
      {
      $errors[] = 'person attend';
   }
   
   
   
      if (empty($_POST['comment']))
      {
      $errors[] = 'Please enter some comment';
      }
      else if (strlen ($_POST['comment']) > 255)
      {
      $errors[] = 'comment ';
  
 }
 
      if(isset($errors))
{

	foreach($errors as $val)
	{
	
		echo "Error: $val <br/>"; 
	}
}
 
 
      if($name !="" && $email!="" && $contact!="" && $person_attend!="" && $comment!="" )
      
      {
 
      //insert statements
 
      } else {
 
      //error message
 
      }
 
      //process form
 
      //this is your add query....
  
      $name = $_POST['name'];
 
      $email = $_POST['email'];
 
      $contact = $_POST['contact'];
 
      $person_attend = $_POST['person_attend'];
  
      $comment = $_POST['comment'];
 
      $query = "INSERT INTO rsvp (id, name, email, contact, person_attend, comment)
   
      VALUES ('', '$name', '$email', '$contact', '$person_attend', '$comment')";
      
      $results = mysql_query($query) or die
  
      ("Could not execute query : $query." . mysql_error());
    
      {
 
      echo "thanks you ";
 
      }
   
      mysql_close();
 }
      

?>
</center>
<center> 
<br>
<a href="Index.php">View list attend</a><br>
<a href="register.html">Clik here to register</a>
</center>

flash it already,but then,still same..query tu db even no data was keyed a the form submit.how to tod?o
?

nav33n 472 Purple hazed! Team Colleague Featured Poster · Answer 12 · 2008-02-14T14:19:25+00:00

:) you have the insert statements outside the loop.
Put

//process form
 
      //this is your add query....
  
      $name = $_POST['name'];
 
      $email = $_POST['email'];
 
      $contact = $_POST['contact'];
 
      $person_attend = $_POST['person_attend'];
  
      $comment = $_POST['comment'];
 
      $query = "INSERT INTO rsvp (id, name, email, contact, person_attend, comment)
   
      VALUES ('', '$name', '$email', '$contact', '$person_attend', '$comment')";
      
      $results = mysql_query($query) or die
  
      ("Could not execute query : $query." . mysql_error());
    
      {
 
      echo "thanks you ";
 
      }
   
      mysql_close();
 }

in place of //insert statements

error

Recommended Answers Collapse Answers

All 17 Replies

Recommended Answers