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Always learner. True believer of mind power.

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17 Posted Topics

Member Avatar for tekagami
Member Avatar for weasel7711

[QUOTE=weasel7711;1067475]This is my first time really using HTML, Javascript and PHP. This is part of a prototype for a project for my SW Eng. course. The problem I am having is that the form is not going through the validation. The user is supposed to be able to search by …

Member Avatar for Airshow
0
172
Member Avatar for rickya100

At a first glance, I can see that on your calling code: [code]<div class="icons"> <a href="#" onmouseover="SwapOut(personal, 0)" onmouseout="SwapBack(personal, 1)"><img name="personal" alt="logo" src="images/personal_up.png" /></a>.... </div> [/code] you are referencing undefined variables. Have you tried to replace the call for: [code] onmouseover="SwapOut(personal, 0)" [/code] with onmouseover="SwapOut('personal', 0)" as I guess you …

Member Avatar for HenryGR
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335
Member Avatar for leegeorg07

[QUOTE=leegeorg07;1010097]Hi, using a snippet I found on here I have this code: [code] var password; var pass1="PASSWORD-HERE"; password=prompt('Whats The Magic Word?',' '); if (password==pass1) alert('That Is Correct!'); else { window.location="SITE-LINK"; } [/code] But I want to make pass1 harder to see so I want to encrypt it and use that …

Member Avatar for HenryGR
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102
Member Avatar for rowads80

As far as I understand, what you need is 1) to create a functions that is called every time your page is loaded; tht's achieved with the onload="myfunction()" attribute within the <body> tag. and 2) the function needs to hold an array of pictures that can be presented randomly. Am …

Member Avatar for JugglerDrummer
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167
Member Avatar for bigalo

The easiest way is to create a new function on you JS code, simple as [code] function exall() { for (inde=1;inde<=5;inde=inde+2) { ToggleRowVisibility("paneltable",inde); } } [/code]

Member Avatar for bigalo
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170
Member Avatar for clhari
Member Avatar for trient

Please specify a bit more. Do you already have a sort of validation function?

Member Avatar for ShawnCplus
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314
Member Avatar for FrankThePostman

You may try to replace your line [code] document.getElementById("full-details").innerHTML=xmlHttp.responseText [/code] with a line like: [code] eval("document.getElementById('"+full-details+"').innerHTML=xmlHttp.responseText"); [/code]

Member Avatar for ~s.o.s~
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3K
Member Avatar for Inny

If you have the image on a server (whichever), just place the url on the "a" tag... [code] <a href="spike.jpg" onclick="this.href = 'javascript:void(0);';"> <img src="http://www.myserver.com/images/spike_thumb.jpg" title="click to expand." style="float:right;" onclick="new ImageExpander(this, 'http://www.myserver2.com/images/spike.jpg');"> </a> [/code]

Member Avatar for Inny
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1K
Member Avatar for deeptiraghu

On every menu, either CSS based or JavaScript based menu, the link is actually achieved by the (X)HTML tag "a". The "target" attribute of the "a" tag tells the browser to remains on same window or create a new one.

Member Avatar for deeptiraghu
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151
Member Avatar for wicket94

Not everybody have DW CS3. If you post the code you are talking about, somebody can figure out your problem, but from the small snippet explanation....

Member Avatar for HenryGR
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77
Member Avatar for Inny

Try to change the random generation to an expression like: [code] topicnum = Math.round(Math.random()*(topiccount-1))+0; [/code]

Member Avatar for Inny
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147
Member Avatar for Gia

You create a new array [code]var images = new Array();[/code] and then you want to reference [code] imgname[0] = 'home.jpg'; ... [/code] ..hmmm! names do not match. Also, creating a new array, does not create a new array if images... you may want to create the elements of the array …

Member Avatar for HenryGR
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154
Member Avatar for tefflox

OK! I've just sent an email from my gmail account with IE7 screenshot. The discrimination works!

Member Avatar for tefflox
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122
Member Avatar for statmatics

Instead of looking for scroll positions relative to the document, I would read mouse's position to find out where to place the <div>. The event element do the trick, so: event.clientX is the x position where the event occurred and event.clientY is the Y position. Then, the code [ICODE]mydiv.style.left = …

Member Avatar for HenryGR
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160
Member Avatar for ced69

There are at least three missing functions: 1. yCoord () 2. placeIt() 3. shiftIt() without them, the code cannot works.

Member Avatar for HenryGR
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86

The End.