codewall

I think try width="100%"

To daniweb please change my username from thecodewall to codewall thanks

you can set the departA and departB to unique or you can add additional condition in your program if you use this sql, check each entry before they inserted into database. SNIP

maybe this help [url]http://codewall.blogspot.com/2010/12/import-csv-file-in-mysql-using.html[/url]

Maybe this help and give you some information, how to create bar graph using Google visualization: [url]http://codewall.blogspot.com/2010/12/google-interactive-bar-chart-for-web.html[/url]

maybe you can join your database tables. Take this another expand collapse, maybe it helps: [url]http://codewall.blogspot.com/2011/01/div-expand-and-collapse-in-javascript.html[/url]

try to echo $MM_redirectLoginSuccess to see what's the value in it.

There are a lot of advantage when using MySQL, its free, SUN Microsystems supported, fast. In MS SQL when you set the size, for example 20 and you put a value more 20 character it will give you an error but when My SQL it will accept only character fit …

I think it's a template found in blogspot gallery they customize to look great.

Maybe you can view this post, hope it will give you some idea to solve your problem. [url]http://codewall.blogspot.com/2011/03/upload-image-in-folder-in-php-step-by.html[/url]

document.getElementById('some_id').style.fontFamily='courier'; document.getElementById('some_id').style.fontFamily='verdana';

The following error occurs because your code displaying some text before processing the header. Try to read this post. [url]http://codewall.blogspot.com/2010/12/php-cannot-send-session-cache-limiter.html[/url] hope it helps...

try this document.zip.submit();

Try to download this application, it used JQuery framework, hope it helps. [url]http://codewall.blogspot.com/2011/03/php-quiz-maker-application.html[/url]

Maybe Javascript can't locate apply id or apply is not located in that page.

Please clarify more your question.

Try to specify css in some browser, try to read this post, hope it helps. [url]http://codewall.blogspot.com/2010/12/specify-css-in-different-browsers.html[/url]

You can use ajax, ajax has a property that you can control and manipulate an event. Maybe this post ca help. [url]http://codewall.blogspot.com/2011/03/learn-what-is-ajax-step-by-step.html[/url]

If you don't want the value to be lost when refresh maybe you can use session variable.

Maybe you can search more js calendar that works in all browser type, for now try this post maybe its help. [url]http://codewall.blogspot.com/2010/12/specify-css-in-different-browsers.html[/url]

try to assign id to your textfield and access it in javascript. Javascript: function a() { document.getElementById('mytext').focus(); } Form: <input type="text" nane="mytext" id="mytext" />

Try to read this post, hope it will help and give you an idea. [url]http://codewall.blogspot.com/2011/01/div-expand-and-collapse-in-javascript.html[/url]

maybe this can help, please read this post. [url]http://codewall.blogspot.com/2011/02/create-simple-menu-in-html.html[/url]

If you have login in your site this is very simple, just create database table containing users who login and you can count it using sql count function when querying. If you don't have try to use Google analytics, its free and you can track your visitors, views and statistics.

You can create database table that have id,image and details, first upload the image first and insert into database table. Since the image have its own unique id you can query the id and assign to hidden textfield in next form(form detail), with this form you can update(insert info) the …

Maybe you can use Javascript language for validation...

try setting z-index to 1000

maybe this help. [url]http://codewall.blogspot.com/2010/12/php-cannot-send-session-cache-limiter.html[/url]

change $num_rows > 0 && $type = 1 $num_rows > 0 && $type = 2 $num_rows > 0 && $type = 3 to $num_rows > 0 && $type == 1 $num_rows > 0 && $type == 2 $num_rows > 0 && $type == 3

maybe you can post some line of your code

maybe this help, this is my login script using jquery [CODE] <?php session_start(); require_once("includes/includes.db.php"); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-1" /> <title>Untitled Document</title> <link type="text/css" href="jquery/css/south-street/jquery-ui-1.8.custom.css" rel="stylesheet" /> <script type="text/javascript" src="jquery/js/jquery-1.4.2.min.js"></script> <script type="text/javascript" src="jquery/js/jquery-ui-1.8.custom.min.js"></script> <script type="text/javascript"> $(function() { username = …

maybe this help [url]http://codewall.blogspot.com/2010/12/simple-login-in-php.html[/url]

maybe you can use [B]distinct [/B]in mysql

I think you can use [B]join[/B], inner join, left join, right join or cross join, ex, select a.numbers,b.numbers from table1 as a inner join table2 as b on a.id = b.id

maybe this help... [url]http://codewall.blogspot.com/2011/01/how-to-read-input-from-console-in-java.html[/url]

try [url]http://www.shadowbox-js.com/[/url] it easy...

its great when you modify this in css

It easy to accomplish this using sever side language. SNIP

what php version are you using?

maybe this help [CODE] import java.io.*; public class ReadFile { public static void main(String[] args) { File file = new File("C:\\sample_text.txt"); FileInputStream fis = null; BufferedInputStream bis = null; DataInputStream dis = null; try { fis = new FileInputStream(file); // Here BufferedInputStream is added for fast reading. bis = new …

If you want xampp (opensource apache mysql php and pearl) you can view my step by step tutorial: [url]http://codewall.blogspot.com/2011/01/how-to-install-xampp-step-by-step.html[/url] or read my of my tutorials regarding mysql in xampp: [url]http://codewall.blogspot.com/p/my-tutorial.html[/url]

you can create php page that includes unset session code then your ajax call this page

I my college days, my project was an IDE for assembly language using java... maybe you can do also the same way...

maybe this can give you an idea [url]http://codewall.blogspot.com/2009/08/toggle-background-color-using.html[/url]

maybe this help <form name='myform' action='page3.html' method='post'> ---- some form elements ---------------- </form>

maybe this help. [url]http://codewall.blogspot.com/2010/12/simple-login-in-php.html[/url]

maybe this help.. removing the spaces before and after text you can use trim() function

if you don't want image path name duplication try to set the field to unique.

maybe you can do this... [CODE] $(document).ready(function () { var x = '- Table1'; $('#table1_head').click(function () { if(x == '- Table1') x = '+ Table1'; else x = '- Table1'; $('#button1 a').replaceWith(x); }); }); [/CODE]

maybe this help [CODE] <script language="javascript"> function addRow(tableID) { var table = document.getElementById(tableID); var rowCount = table.rows.length; var row = table.insertRow(rowCount); var cella = row.insertCell(0); cella.style.backgroundColor='#FF0000'; var element1 = document.createElement("input"); element1.type = "text"; element1.name = "txtManufacturer[]"; element1.size = "10"; cella.appendChild(element1); } </script> [/CODE]