Would I have to go about doing the math manually and make my own function? Is there some built in function I can use to be lazy? Is there some totally easier way that I am oblivious to?

I found this link, which you could use to do the decimal to hex number.

But, I'd imagine somewhere there's bound to be some kind of library function that could do this …

## All 3 Replies

I found this link, which you could use to do the decimal to hex number.

But, I'd imagine somewhere there's bound to be some kind of library function that could do this for you... Have you searched Google for it yet?

Would I have to go about doing the math manually and make my own function? Is there some built in function I can use to be lazy? Is there some totally easier way that I am oblivious to?

I will assume you mean you would like to display the value of some integral type in decimal, binary, octal, and hexadecimal representations. Three out of four are available the lazy way, but you'll need to roll your own to display a binary representation.

``````#include <iostream>

template < typename T >
inline T highbit(T& t)
{
return t = (((T)(-1)) >> 1) + 1;
}

template < typename T >
std::ostream& bin(T& value, std::ostream &o)
{
for ( T bit = highbit(bit); bit; bit >>= 1 )
{
o << ( ( value & bit ) ? '1' : '0' );
}
return o;
}

int main()
{
unsigned long value = 0x12345678;
std::cout << "hex: " << std::hex << value << std::endl;
std::cout << "dec: " << std::dec << value << std::endl;
std::cout << "oct: " << std::oct << value << std::endl;
std::cout << "bin: ";
bin(value, std::cout);
std::cout << std::endl;
return 0;
}

/* my output
hex: 12345678
dec: 305419896
oct: 2215053170
bin: 00010010001101000101011001111000
*/``````

Yeah, I did search Google. Amazingly hard to find things sometimes... But thanks everyone.:cheesy:

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