## Rotvailera

help me with this program :

#include <iostream>
using namespace std;

#include <math.h>

double F(double x){
double res = pow(x, 9) - pow(x, 7) + 2 * pow(x, 2) -1;

return res;
}

void print_roots(){
double low = 0, high = 1;

for(int i = 0; i < 1000 ; ++i){
double mid = (float)(low + high)/2;
double val = F(mid);

cout << mid << ":" << val << endl;

if(val < 0.00001 && val > -0.00001){
cout << "Root is " << mid << endl;
return;
}
else if (val < 0 )
low = mid;
else
high = mid;
}
}

int main(int argc, char **argv){
print_roots();
system("pause");
return 0;
}

i mean to assign a task and interval and the program to give resolution.
example : i start the program and it ask me to enter the task(bisection method) after entering it to ask me the intervals and when we do this to show the answer.

## Lerner 582

Yes, you should be able to do that. You might want to look up use of switch statements and use a menu to select the task. Here's a rough sketch of the process, but looking it up in a book to learn the details is strongly recommended.

cout  << enter the number before the task you want to do
cout << 1) bisection
cout << 2) foo
cout << 3) bar

cin >> selection
switch(selection)
{
case 1:
cout << "enter the interval you wish to use
cin >> interval
bisection(interval);
break;
case 2:
foo();
break;
case 3:
bar();
break;
}

There are alternative ways to accomplish the same thing, but this is usually one of the easier methods to understand.