You can try to bruteforce it out and just increment by 0.01 maybe that will work out.
But the answer wouldnt be exact.
So u can try in for an approx val.
Then test it up. If the value you got. is squared is lesser than the main number of which you should find the square root then increment. But if the the square of the value increases take the previous number as the approximate square root. So you will only be missing the minutest details
Help! I want to create a java program that finds the highest even integer among the values entered by the user. Stop asking values when a value less than 1 have been entered. If no even integer is entered, display "No Even Integer"
Hi, as I was told that my code doesn’t scale well at all, I thought perhaps I’d try to get a better understanding of interfaces/abstract classes and classes and the relationship between them.
I don’t want at this stage work on a big separate project as I've already got plenty ...