Hello everyone,
I need help with this code, which does not work properly. It prints fine at the first instant and when I convert it into a double it prints some unknown value. I am trying to get the maximum of all the values in the row. First: I cant figure out how to exclude the first value of the row, which is just a indicator of how many values are in the row (shown here in bold). Second: I cant get the conversion to a float so I can do the comparison. I thank you in advance for helping me out.
Best,
newbie

the test.grf file

"IngWater_HumRcp",3,"FLOAT",0,"mg/kg-d",
1,4,
10,2.657374814e-012,2.658182387e-012,2.658989959e-012,2.659797532e-012,2.660605104e-012,2.661412675e-012,2.662220249e-012,2.663027821e-012,2.663835392e-012,2.664642966e-012,

The code:

#include <stdio.h>
#include <iostream>
#include <string.h>

int main()
{
    char sizeLineInput[40980];
    char *token;
    char c;
    int idx=0;
    char num[15];
    double array[10000], ADD; // Declare an array of 10,000
    int n = 0;
    char * pEnd;


    FILE *SourceFile = fopen ("c:\\Temp\\test.grf","r");
    if (SourceFile != NULL)
    {
       while(fgets(sizeLineInput, 10000, SourceFile)!=NULL)
       {
        token = strstr(sizeLineInput ,"IngWater_HumRcp");
        if (token)
        {
         fgets(sizeLineInput, 10000, SourceFile);
         while((c=fgetc(SourceFile))!='\\')
         {
          if(c==',')
          {
           num[idx]=0;
           n++;
           printf("%s\n",num); // Here it prints right
           array[n]= atof(num);
           //array[n]= strtod (num,&pEnd);
           printf("%d\n", array[n]); // Here it doesnot
           system("PAUSE");
           idx=0;
          }
          else
          {
           num[idx] = c;
           idx++;
          }
         }
        }
       }
    }
for (int i=0;i<n;i++){
if (array[i+1]>array[i]){
ADD=array[i+1];}
else
ADD=array[i];
}
return 0;
printf("%s\n",ADD);
system("PAUSE");
}

line 32 is a string in scientific notation. The value is just too small to be represented in normal double precision, so you have to display it in scientific notation, like this: printf("%e\n", array[n]); // Here it doesnot In the value 2.657374814e-012 the -012 tells you to move the decimal point 12 places to the left, which makes the number 0.00000000000265..., a very very tiny number.

Edited 7 Years Ago by Ancient Dragon: n/a

Thank you very much. It worked. U did saved me a lot of time, energy and frustration.

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