Add 1.0/1.0+1.0/2.0+... when you do integer division (e.g., 1/2) regardless of the variable the result is going into it still still gets truncated. If you haven't already make sure your result is declared as type double otherwise nothing will work.

#include <iostream>
using namespace std;
void main ()
{
double sum, i;
sum=0;
for (i = 0, sum = 0; i <= 10; i++)
sum = sum +i(1.0\i);
cout << "Sum is " << sum << endl;
}

to dived you use / not \. also i(...) is not valid. if you want to multiply i by that quantity you have to do i * (1.0 / i) . Also please use code tags. the link to explian them is http://www.daniweb.com/forums/announcement8-3.html

It didn't work because u are making sum zero in each iteration of the loop .. so just remove sum=0 from the loop.. it's enough to initialize it before the loop.

i.e:
sum=0;
for (i = 0; i <= 10; i++)
sum = sum +i(1.0\i);

sum = sum +i(1.0\i); That's you're killer. First of all, use the correct division symbol: /
Secondly, why is there an 'i' in front of the division?
That statement, corrected, should be:
sum = sum + ( 1.0 / i );

But in the loop's first iteration, you add 1.0 / 0, which is...um....not defined mathematically. In actuality, you get a really huge result.

It didn't work because u are making sum zero in each iteration of the loop .. so just remove sum=0 from the loop.. it's enough to initialize it before the loop.
i.e:
sum=0;
for (i = 0; i <= 10; i++)
sum = sum +i(1.0\i);

While I agree it looks better to initialize sum outside the loop, it is NOT being reset to 0 each iteration, any more than counter i is. The initialization statement is executed only once.

I want to implement undo logic which deletes the last drawn shape. To test this logic i had cleared shapes list and redrawn all shapes but still last ...