Im having trouble sending a bool type to a function which returns a char string to a string.

I have provided the code below

/*
  Name: bool2.cpp   
  Copyright: 
  Author: Toshkin   
  Date: 06/09/05 21:56
  Description: passing string to boolean function returning boolean to 
*/

#include <iostream>
#include <cstring>
using namespace std;



bool inout(char *string); // function prototype
char outin(char *string,bool *bl);     //
int main()
{
    char str1[5];
    bool b;
    cout <<"Please enter the word \"in\" or \"out\": ";
    cin >>str1;
    /*if (strcmp (str1,"in") == 0) {        // redundant code....
             b = true;
             }
    else {
         b = false;
         }
    */
    b = inout(str1);
    cout << boolalpha << b << endl;
    cout <<"str1: "<<str1<<endl;
    outin(str1,b);
    cout <<"str1: "<<str1<<endl;
    system("PAUSE");
    return 0;
}

bool inout(char *string)                             // this works
{
     
     if (strcmp(string,"in") == 0){
        return true;
        }
     else if (strcmp(string,"out") == 0){
        return false;
          }
     
} // end inout

char outin(char *string,bool *bl)                    //  this doesn't work
{
    
     if (bl==1){
            string = "in";
            }
     else if (bl==0) {
          string = "out";
          }
     return string;
}

Im using Bloodshed DevC++ 4.9.9.2
Your help will be greatly appreciated.
Cheers Toshkin!!!

You can't return arrays in C or C++. Nor can you copy arrays using assignment [edit]use strcpy to copy strings[/edit]. Is there some reason you aren't using std::string?

Im having trouble sending a bool type to a function which returns a char string to a string.

I have provided the code below

char outin(char *string,bool *bl)                    //  this doesn't work
{
    
     if (bl==1){
            string = "in";
            }
     else if (bl==0) {
          string = "out";
          }
     return string;
}

Im using Bloodshed DevC++ 4.9.9.2
Your help will be greatly appreciated.
Cheers Toshkin!!!

since you are passing the string in by pointer and not by value, you can directly alter the string in the function... however you can not simply do string = whatever... you need to do a strcpy(string, whatever) or if you want, use stricpy(string, whatever, length) and then remember to put the null terminator at the end... then your function doesn't need to return anything... both strcpy and stricpy are in <cstring> and you'll need to #include that

also when comparing a bool to a value you can simply write true or false instead of 0 and 1... works better for clarity purposes... makes it easier to read

hope this helps

This will work -- the function must return char* which is a pointer just like the parameter. But there is no point passing the parameter if the function is going to change and return the pointer.

char* outin(char *string,bool *bl)
{
    
     if (bl==1){
            string = "in";
            }
     else if (bl==0) {
          string = "out";
          }
     return string;
}

This would be more logical. And why are you passing the bool by reference instead of by value? The function isn't changing the value so you might as well pass by value.

char* outin(bool bl)
{
    char* string = 0;
     if (bl==1){
            string = "in";
            }
     else if (bl==0) {
          string = "out";
          }
     return string;
}

Just a quick thanks for all the guys.

Cheers Toshkin!!! :D

PS. Sorry for the late reply.

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