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Write a program to sort 20 decimal numbers in decreasing order and print the
result.
i have solution but lengthy.

decimal[] arr = { 12.3m, 45.2m, 5.4m, 23.44m, 43.21m, 31.34m, 4.3m, 21.3m,
34.2m, 32.1m, 44.2m, 6.4m, 64.3m, 3.4m, 5.32m, 32.345m, 4.34m, 23.4m,
45.234m, 5.31m };
for (int i = 0; i < arr.Length; i++)
{
Console.WriteLine(arr[i]);
}
Console.WriteLine("\n--Number in decreasing order--\n");
int count = 0;
while (count < arr.Length - 1)
{
if (arr[count] < arr[count + 1])
{
decimal temp = arr[count];
arr[count] = arr[count + 1];
arr[count + 1] = temp;
count = 0;
continue;
}
count++;
}
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Last Post by Diamonddrake
0

I did an example of sorting number, and I used a generic list. I copied your values from decimal array to list<decimal> and did what you have requested.
I hope you like it. Its fast and simple - and it works :)

private void method()
        {
            decimal[] arr = new decimal[] { 12.3m, 45.2m, 5.4m, 23.44m, 43.21m, 31.34m, 4.3m, 21.3m, 32.1m, 44.2m, 
                              6.4m, 64.3m, 3.4m, 5.32m, 32.345m, 4.34m, 23.4m, 45.234m, 5.31m };
            List<decimal> list = new List<decimal>();
            for (int i = 0; i < arr.Length; i++)
            {
                list.Add(arr[i]);
            });
            //pG.aL = pG.aL.OrderBy(a => a.number).ToList();
            list = list.OrderBy(a => a).ToList();
            list.Reverse();
        }

Mitja

0

The simplest solution would be to just call sort on the array, and if necessary reverse it as posted above, but there becomes a sorting issues between logical and natural order. if the decimals are not padded with zeros, it could get out of order. as in 10,1,2,3...9 instead of 1,2,3...9,10 because of that logical something before nothing clause.

this is simply overcome by using a numericcomparer class

NumericComparer ns = new NumericComparer();
Array.Sort(arraytosort, ns);
arraytosort.Reverse();
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