how can i shorten this IF condition using array?

[gingerfish]

here is my code:

//if any of errprLists is not equal to 0, then initialWieght equals newWeight
if(errorList[0]!=0 || errorList[1]!=0 || errorList[2]!=0 || errorList[3]!=0)
    {
        for(int i=0; i<row; i++)
        {

        initialWeight[i] = newWeight[i];
            
        }
    }

    //break the loop if all errors equal 0
    //---------------------------------------------------------------------------
    else if(errorList[0]==0 && errorList[1]==0 && errorList[2]==0 && errorList[3]==0)
        break;

what i want to do is to shorten those errorLists, but i dont know how to do it
when i write

for(int j=0; j<errorList.length; j++){
    if(errorList[j]!=0) ....
}

it doesnt work
please help
thanks
:(

[monarchmk]

You basically try to find if any of error list are equal or not equal to 0
Then put some sumerr integer and get sum of all errorLists...

int errsum=0;
for (int j=0;j<errorList.length;j++)
     errsum+=errorList[J]; // i'll make sum of all  errorList.If some of ErrLists are != 0 then sum is != 0

//Now check if sum is or not is equal to 0

  if (errsum ==0)
  {
    break; //you want to break if all are equal to 0you code if equal
  }
  else
  {
    //Your code if not equal
    for(int i=0; i<row; i++)
    {
        initialWeight[i] = newWeight[i];
    }
  }

[quuba]

boolean all() {
        //&&
        int counter = 0;
        for (int j = 0; j < errorList.length; j++) {
            if (errorList[j] == 0) {
                counter++;
            }
        }
        return counter == errorList.length;
    }

    boolean oneOf() {
        //||
        for (int j = 0; j < errorList.length; j++) {
            if (errorList[j] != 0) {
                return true;
            }
        }
        return false;
    }
...

        if (oneOf()) {
            System.arraycopy(newWeight, 0, initialWeight, 0, row);
        }

...

useful: http://en.wikipedia.org/wiki/De_Morgan's_laws

[gingerfish]

You basically try to find if any of error list are equal or not equal to 0
Then put some sumerr integer and get sum of all errorLists...

int errsum=0;
for (int j=0;j<errorList.length;j++)
     errsum+=errorList[J]; // i'll make sum of all  errorList.If some of ErrLists are != 0 then sum is != 0

//Now check if sum is or not is equal to 0

  if (errsum ==0)
  {
    break; //you want to break if all are equal to 0you code if equal
  }
  else
  {
    //Your code if not equal
    for(int i=0; i<row; i++)
    {
        initialWeight[i] = newWeight[i];
    }
  }

Thank you so much :)

[gingerfish]

boolean all() {
        //&&
        int counter = 0;
        for (int j = 0; j < errorList.length; j++) {
            if (errorList[j] == 0) {
                counter++;
            }
        }
        return counter == errorList.length;
    }

    boolean oneOf() {
        //||
        for (int j = 0; j < errorList.length; j++) {
            if (errorList[j] != 0) {
                return true;
            }
        }
        return false;
    }
...

        if (oneOf()) {
            System.arraycopy(newWeight, 0, initialWeight, 0, row);
        }

...

useful: http://en.wikipedia.org/wiki/De_Morgan's_laws

Thank you so much :)