Hi guys im trying to make a program that will work as " Slot Machine " and im stuck in one part that i can not resolve. Im trying to verify predetermined char in random array so i can know if some of the three char appear three times or more. I want to do that so i can deteremined how much player is going to win. Im new to programming so i would appreciate any help that i can get. Here is a part of my code that i need help with.

``````srand ( time(0));

char sign;
sign  = '\$';
sign  = 'X';
sign  = 'O';

for (char i = 0; i < 3; ++i)
{
char r  = rand() % 3;
char s  = rand() % 3;
char d  = rand() % 3;

cout << "___ ___ ___\n";
cout << " "<<sign[r]<< " | " << sign[s] << " | " << sign[d] << " | " << "\n";
cout << "___|___|___|\n";

}``````

## Recommended Answers

Im trying to verify predetermined char in random array so i can know if some of the three char appear three times or more.

i would probably write a function that will return the number of occurances the desired char appears in your array. then you can test for this …

## All 3 Replies

Im trying to verify predetermined char in random array so i can know if some of the three char appear three times or more.

i would probably write a function that will return the number of occurances the desired char appears in your array. then you can test for this condition and handle it accordingly:

``````int get_occurances(char array[], int& size, char& target)
{
int counter = 0;

for(int i=0; i<size; i++)
{
if(array[i] == target)
{
counter++;
}
}

return counter;
}``````

or you can just use the cout() function from the <algorithm> library:

``````#include <algorithm>

int counter = 0;

counter = count(&array, &array[size], target);

//handle the case of the desired char occuring more than 3 times
if(target > 3)
{
//do whatever you wanted to do here
}``````

Ty for your help and excuse my stupid question but i dont know where to put in this code. Like i said before im really fresh in programming.

I think what you want to see is if the combination of (r,s,d) results in some winning combination? Is that correct. For example if R = \$ and S = \$ and D = \$, then you would win some large amount? If so then you can simply do something like this:

``````for (char i = 0; i < 3; ++i)
{
char r  = rand() % 3;
char s  = rand() % 3;
char d  = rand() % 3;

cout << "___ ___ ___\n";
cout << " "<<sign[r]<< " | " << sign[s] << " | " << sign[d] << " | " << "\n";
cout << "___|___|___|\n";

if(r == s && s == d && d == '\$') { //if r = \$ and s = \$ and d = \$
cout << "JACKPOT!!!!\n";
}else if(r == s && s == d && d == 'X'){ // if r == X and s == X and d == X
cout << "You won \$500 \n";
}else if(r == s && s == d && d == 'O') //  if r == O and s == O and d == O
cout << "You won \$100 \n";
} else{
cout << "You won nothing :(\n";
}
}``````

You can create a function to automate and remove the redundancy if you need to.

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