Hey, guy I'm having some trouble with my function see below:

bool tryAgain()
{
    char answer;

    cout << "Do you want to enter another number? (Y/N): ";
    cin >> answer;
    answer = toupper(answer);

    while(answer != 'Y' || answer != 'N')
    {
        cin.clear();
        cin.ignore(10, '\n');
        cout << "Input invalid." << endl;
        cout << "Do you want to enter another number? (Y/N): ";
        cin >> answer;
        answer = toupper(answer);
    }

    if(answer == 'Y')
    {
        return true;
    }
    else
    {
        return false;
    }
}

the function enters the while loop even when a correct answer is inputted from the get go & if I do enter the while loop I get stuck even though I enter a correct answer. To me this logic makes sense, break the loop when the input is == 'Y' || 'N', but its keeps looping. Help me see my logical error! Thanks for your help.

You want both conditions to be true; that requires the && operator. What you are asking is for is for either condition to be true (which will always be the case since answer can not be both values at the same time).

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