Hey bros. I made a program that prints out random numbers in a linked list. I want to have the index number next to each of the random numbers in the list. I guess for example like:
1 25
2 123
3 56

Here's m program so far, and it only sorts and prints out the list, but doesn't have an index next to each random integer. I think you use a list iterator to do this, but I can't figure it out... my output right now is like [23 58 129] but I kinda of want it to be like the list I made above.
Here's the code.

import java.util.*;
import java.io.IOException;
import java.util.Scanner;
import java.util.Random;

public class LinkedListProgram
    public static void main(String[] args) throws IOException
        int i,number, ran;
        Scanner sc = new Scanner(System.in);
        LinkedList<Integer> list = new LinkedList<Integer>();
        ListIterator li;
        String line;
        Random random = new Random();
        int pick = random.nextInt(150);
        System.out.println("Enter # of nodes");
        number = sc.nextInt();
        if (number > 0)
            for (i = 0; i < number; i++)
            list.add(1+ (int)(Math.random()*150));
            System.out.print(list + "\n");

                System.out.println("\nnumber is less than 0\n");

Any helps is SUUUUPER APRECIATED. Thanks so much for all your times!

6 Years
Discussion Span
Last Post by NormR1

You will have to write a loop to get each element from the list one by one so you can print its value with its position in the list.

Edited by NormR1

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