what exactly do you mean? a matrix with random number of rows and columns? a matrix that contains random numbers? Both?

In order to work with a matrix with random number of rows and columns you need to know how to work with pointers, each dimension requires one star, so in a 2d matrix you would have int** array, after that call malloc() to allocate each dimension of the array. Some of the code below may now compile with older C compilers.

int** matrix = 0;
int i;
const int rows = 5;
const int cols = 10;
matrix = (int **)malloc(rows * sizeof(int *)); // allocate rows
// now allocate the columns
for(i = 0; i < rows; i++)
matrix[i] = (int *)malloc(rows * sizeof(int));

I've built my program without pointer I think thats why the result was wrong!
I need 2 2D matrix (2x4)and (4x3) which contain random numbers between -100 and 80 .

Can I send to u a private message I have a strong excuse to do that and I will tell you why later on if u accept !

Please read my signature -- I don't accept private messages.

If you know the size of the matrixes then you don't need pointers. Just call rand() to fill the matrices with random numbers. Here is another thread that may help you.

Write a C program that should create a 10 element array of random integers (0 to 9). The program should total all of the numbers in the odd positions of the array and compare them with the total of the numbers in the even positions of the array and indicate ...

Hi. so this is actually a continuation from another question of mineHere but i was advised to start a new thread as the original question was already answered.

This is the result of previous question answered :

I have a 2d matrix with dimension (3, n) called A, I want to calculate the normalization and cross product of two arrays (b,z) (see the code please) for each column (for the first column, then the second one and so on).
the function that I created to find the ...