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This Programs is a Simple Calculator that usses Arrays and pointers.
Currently a freshman student and im completely lost on the errors i keep on getting

#include<stdio.h>
#include <conio.h>

main()
{
    clrscr();

    int num1[5],num2[5],sum[5],*n1,*n2,x;
    char oper[4],*o;
    *n1 =num1[5];
    *n2 =num2[5]
    *o = oper[4];
    oper[0] ='*';
    oper[1] ='+';
    oper[2] ='-';
    oper[3] ='/';

    gotoxy(3,1);printf("_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ ");
    gotoxy(3,2);printf("");
    gotoxy(3,4);printf("           _____   _____   _____ = _____   ");
    gotoxy(3,6);printf("           _____   _____   _____ = _____   ");
    gotoxy(3,8);printf("           _____   _____   _____ = _____   ");
    gotoxy(3,10);printf("          _____   _____   _____ = _____   ");
    gotoxy(3,12);printf("          _____   _____   _____ = _____   ");
    gotoxy(3,19);printf("_ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ ");

    {
        {
            x = 4;
            if(*o=='+');
            gotoxy(3,x);printf("%d\t%c\t%d\t%d",*n1,*o,*n2,sum);
            sum =*n1 + *n2;
            if(*o=='/');
            gotoxy(3,x);printf("%d\t%c\t%d\t%d",*n1,*o,*n2,sum);
            sum =*n1 / *n2;
            if(*o=='*');
            gotoxy(3,x);printf("%d\t%c\t%d\t%d",*n1,*o,*n2,sum);
            sum =*n1 * *n2;
            if(*o=='-');
            gotoxy(3,x);printf("%d\t%c\t%d\t%d",*n1,*o,*n2,sum);
            sum =*n1 - *n2;
            if(*o=='+');
            *n1++;
            *n2++;
            x++;
            else();
            printf("\n\nERROR");
        }

        getch();
        return 0;
    }
}

Are you using an apple computer? If you are than this is an error.

2:10: fatal error: 'conio.h' file not found
#include <conio.h>

I'm sorry if I didn't help that much.

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