#include <stdio.h>
#define N 40
void sum(int*p, int n, int d[])
  int i;
  *p = 0;
  for(i = 0; i < n; ++i)
     *p = *p + d[i];
int main()
   int i;
   int accum = 0;
   int data[N];
   for(i = 0; i < N; ++i)

      data[i] = i;

    sum(&accum, N, data);
    printf("sum is %d\n", accum);
return 0;

Recommended Answers

All 2 Replies

So what have you tried so far?

My guess is that if you try to compile this with a C++ compiler, it will work just fine. So, why do you need to convert it further?

(btw, I have my suspicions, I'm no fool)

In any case, you need to show that you tried something. We will not just do a "conversion" to C++ for you.

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