When I run:

dec = 255
print hex(dec)

I get 0xff, but I like to get just 'ff'

Recommended Answers

This should do what you want:

print "%x" % 255
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When I run:

dec = 255
print hex(dec)

I get 0xff, but I like to get just 'ff'

'0x' always appears in front, so if you want to use hex() and get rid of 0x, use hex(255)[2:]

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All 7 Replies

This should do what you want:

print "%x" % 255

When I run:

dec = 255
print hex(dec)

I get 0xff, but I like to get just 'ff'

'0x' always appears in front, so if you want to use hex() and get rid of 0x, use hex(255)[2:]

a=input("enter number in decimal :")

def cal(a):
    if a<10:
        b=str(a)
    elif a==10:
        b="A"
    elif a==11:
        b="B"
    elif a==12:
        b="C"
    elif a==13:
        b="D"
    elif a==14:
        b="E"
    else:
        b="F"
    return b
b=a
L1=""
while True:
    c=b%16
    if b<16:
        L1=L1+cal(c)
        break
    else:
        L1=L1+cal(c)
    b=b/16
c=""
for i in reversed(L1):
    c=c+i
print c

this might be a bit cleaner than warunn's code

h=[str(i) for i in range(10)]+["A","B","C","D","E","F"]

def hexa(dec):
    s=""
    while dec:
        s+=h[dec%16]
        dec//=16
    return s[::-1]

What about this:

d = 30
hex(d).split('x')[1]
'1e'

The other question is, does your hex string convert back to decimal?

a = 255

hx = hex(a)
print(hx)
print(int(hx, 16))

hx = hex(a)[2:]
print(hx)
print(int(hx, 16))

''' output -->
0xff
255
ff
255
'''
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