#include<iostream.h>
#include<math.h>
void main()
{
float x,y;
cout<<"Please enter one number ";
cin>>x;
y=x*x;
cout<<"The square of the number you enter is "<<y<<endl;
}
:eek: Pls help... thx u very much...
#include<iostream.h>
#include<math.h>
void main()
{
float x,y;
cout<<"Please enter one number ";
cin>>x;
y=x*x;
cout<<"The square of the number you enter is "<<y<<endl;
}
:eek: Pls help... thx u very much...
Use a loop.
#include <iostream>
using std::cout;
using std::cin;
using std::endl;
int main()
{
for ( ;/* your condition here*/; )
{
float x,y;
cout << "Please enter one number ";
cin >> x;
y = x * x;
cout << "The square of the number you enter is " << y << endl;
}
return 0;
}
hello everyone
try this
#include<iostream.h>
#include<math.h>
void main()
{
float x,y;
while(1)
{
cout<<"Please enter one number ";
cin>>x;
y=x*x;
cout<<"The square of the number you enter is "<<y<<endl;
if (x < 0)
{
break;
}
}
}
This loop goes on forever until the user inputs a negative number and then the loop is broken and the program ends unlike the for loop which has a fixed number of loops.
Yours Sincerely
Richard West