finding the even and odd number from the array

[Mohammed_9]

Using swift programming

import UIKit

var str = "Hello, playground"

func ls(array: [Int]) -> (large: Int, small: Int)//function

{
    var lar = array[0] // array of large number
    var sma = array[0] // array of small number
    let num = 0 // check odd or even

    for i in array[1..<array.count] {
        if i < sma && num % 2 == 0  {
            sma = i
        }else
            if (i > lar) {
            lar = i

        } else
                if num  % 2 == 0 {
            print("this is an even number")
        } else
                {
            print("this is an odd number")
        }

    }
    return (lar, sma)
}
let num = ls(array: [40,12,-5,78,98])
print("Largest number is: \(num.large )  \("\n") smallest number is: \( num.small)")

[JamesCherrill]

OK, that's neat code. Did you have a question?

[Mohammed_9]

It doesn't show the even or odd number

[JamesCherrill]

That's because you have the if test for even/odd tangled up with the if tests for largest/smallest. Right now you don't get to the even/odd code (lines 20-25) if the number matches either of the if tests on lines 13 and 16.
You need to separate the largest/smallest stuff from the even/odd stuff

if is largest so far ...
else if is smallest so far ...

if is even ...
else ...

[Mohammed_9]

s

[JamesCherrill]

You still didn't separate the two sets of if tests - the else on line 21 is creating the problem.
Look again at the if/else structure I showed you in my previous post. See how yours is different?