I'm writing a simple weblog, and I'm new to PHP; but thanks to this particular resource, I'm learning more and more. With that said, I'm making some mistakes, which I need help finding solutions for. I'm receiving these three Warning/Errors:

Warning: mysql_query() [function.mysql-query]: Access denied for user 'root'@'localhost' (using password: NO) in /Users/laurenyoung/Sites/blogtastic/viewcat.php on line 20

Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in /Users/laurenyoung/Sites/blogtastic/viewcat.php on line 20

Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /Users/laurenyoung/Sites/blogtastic/viewcat.php on line 22

And my code is:

<?php
require("includes/config.php");

if(isset($_GET['id']) == TRUE) {
   if(is_numeric($id) == FALSE) {
	$error = 1;
}
if($error == 1) {
   header("Location: " . $config_basedir . "/viewcat.php");
}
else {
   $validcat = $_GET['id'];
}
	}
else {
   $validcat = 0;
}

$sql = "SELECT * FROM categories";
$result = mysql_query($sql);

while($row = mysql_fetch_assoc($result)) {
   if($validcat == $row['id']) {
	echo "<strong>" . $row['cat'] . "</strong><br />";		
	$entriessql = "SELECT * FROM entries WHERE cat_id = " . $validcat ." ORDER BY dateposted DESC;";
	$entriesres = mysql_query($entriessql);
	$numrows_entries = mysql_num_rows($entriesres);
		
	echo "<ul>";
		
	if($numrows_entries == 0) {
		echo "<li>No entries!</li>";
		}
		else {
			while($entriesrow = mysql_fetch_assoc($entriesres)) {				echo "<li>" . date("D jS F Y g.iA", strtotime($entriesrow['dateposted'])) ." - <a href='viewentry.php?id=" . $entriesrow['id'] . "'>" . $entriesrow['subject'] ."</a></li>";
						}
		}
		echo "</ul>";
   }
   else {
	echo "<a href='viewcat.php?id=" . $row['id'] . "'>" . $row['cat'] .
		"</a><br />";
	}
}
require("includes/footer.php");
?>

Could someone <kindly> explain what my issue is here?

Thanks

It's your apache or mysql turned off.try to turn it on and see what happens...

It's turned on. So that's not it. Thanks, though.

Check for connection string in your script. Its unable to connect. $connection =mysql_connect("host","user","password") or die (mysql_error()); Will give you the correct error message.