Can anyone help me here, I want to display an image using the path of the image and the image title from a mysql db?

I can upload the info to the db, but I have trouble displaying the image.
Here is the code:

CREATE TABLE `trailer` (
  `title` varchar(64) NOT NULL,
  `model` text NOT NULL,
  `year` text NOT NULL,
  `price` text NOT NULL,
  `location` text NOT NULL,
  `path` text NOT NULL,
  PRIMARY KEY  (`id`)
$db_host = 'localhost'; // don't forget to change 
$db_user = 'root'; 
$db_pwd = 'colum';
$database = 'colum';
$table = 'trailer';// use the same name as SQL table
$password = 'kinefad';// simple upload restriction,// to disallow uploading to everyone
if (!mysql_connect($db_host, $db_user, $db_pwd))    
	die("Can't connect to database");
if (!mysql_select_db($database))    
	die("Can't select database");
// This function makes usage of// $_GET, $_POST, etc... variables
// completly safe in SQL queries
function sql_safe($s){    
	if (get_magic_quotes_gpc())        
		$s = stripslashes($s);    
	return mysql_real_escape_string($s);
// If user pressed submit in one of the forms
if ($_SERVER['REQUEST_METHOD'] == 'POST'){    
	// cleaning title field    
	$title = trim(sql_safe($_POST['title']));  
	$model = trim(sql_safe($_POST['model']));
	$year = trim(sql_safe($_POST['year']));
	$price = trim(sql_safe($_POST['price']));
	$location = trim(sql_safe($_POST['location']));
	$path = './images/';
if ($title == '') // if title is not set        
		$title = '(empty title)';// use (empty title) string    
	if ($_POST['password'] != $password)  // cheking passwors        
		$msg = 'Error: wrong upload password';    
	if (isset($_FILES['photo']))        
		if (!isset($msg)) // If there was no error            
			// Preparing data to be used in MySQL query                
			mysql_query("INSERT INTO {$table} SET 

			$msg = 'Success: image uploaded';            
	elseif (isset($_GET['title']))      // isset(..title) needed            
		$msg = 'Error: file not loaded';
			// to make sure we've using                                            
			// upload form, not form                                            
			// for deletion           
	if (isset($_POST['del'])) // If used selected some photo to delete        
	{                         // in 'uploaded images form';            
		$id = intval($_POST['del']);            
		mysql_query("DELETE FROM {$table} WHERE id=$id");            
		$msg = 'Photo deleted';        
<title>Administration Page</title>
if (isset($msg)) // this is special section for                 
		// outputing message
<p style="font-weight: bold;"><?=$msg?>
<a href="<?=$PHP_SELF?>">reload page</a>
<!-- I've added reloading link, because     
	refreshing POST queries is not good idea -->
<h1>Administration Page
<h2>Uploaded images:</h2>
<form action="<?=$PHP_SELF?>" method="post">
<!-- This form is used for image deletion -->

<h2>Upload new image:</h2>
<form action="<?=$PHP_SELF?>" method="POST" enctype="multipart/form-data">
<label for="title">Title:</label><br>
<input type="text" name="title" id="title" size="64"><br><br>
<label for="model">Model:</label><br>
<input type="text" name="model" id="model" size="64"><br><br>
<label for="year">Year:</label><br>
<input type="text" name="year" id="year" size="64"><br><br>
<label for="price">Price:</label><br>
<input type="text" name="price" id="price" size="64"><br><br>
<label for="location">Location:</label><br>
<input type="text" name="location" id="location" size="64"><br><br>
<label for="photo">Photo:</label><br>
<input type="file" name="photo" id="photo"><br><br>
<label for="password">Password:</label><br>
<input type="password" name="password" id="password"><br><br>
<input type="submit" value="upload">

Here is my bad attempt of the display page:

$dbcnx = @mysql_connect("localhost", "root", "colum"); 

if (!$dbcnx) 
echo( "connection to database server failed!" ); 

if (! @mysql_select_db("colum") ) 
echo( "Image Database Not Available!" ); 

$result = @mysql_query("SELECT * FROM trailer WHERE id=1"); 

if (!$result) 
echo("Error performing query: " . mysql_error() . ""); 

while ( $row = mysql_fetch_array($result) ) 
$title = $row["title"];
$path = $row["path"];




<img src="images/$title.JPG"> 



Can anyone help me as to where or what I am doing wrong here?


8 Years
Discussion Span
Last Post by kvdd
This article has been dead for over six months. Start a new discussion instead.
Have something to contribute to this discussion? Please be thoughtful, detailed and courteous, and be sure to adhere to our posting rules.