0
<script type="text/javascript">
function submitmyform(){
{
var docx = document.getElementById(formID)
  document.docx.submit();
  setTimeout(function(){self.close();}, 10);
}}
</script>



<?php
$xyz=20;
$stackid=0;
while($stackid<$xyz){
echo'<div align="right">
<form id="'.$stackid.'" name="'.$stackid.'" method="POST" action="updates/comment.php">
<table bgcolor="#E4EFF8" border="0" width="90%" style="border-collapse: collapse" id="table1"><tr>
<td align="left"></font></td>
<td align="right"><font size="2" face="Verdana"><a href="#div'.$stackid.'" onclick="toggle('.$stackid.')">Comment</a> | Rate&nbsp;</font></td></tr>
<tr><td colspan="2"  align="center"  bgcolor="#E4EFF8">
<textarea rows="1" name="S1" cols="45"></textarea></td></tr>
<tr><td colspan="2"  height="24" align="center"  bgcolor="#E4EFF8">
<a href="javascript: submitmyform()"><img border="0" src="buttons/button_c.png"></a><input type="submit" value="Submit" name="B1"></td></tr>
</table></form>
</div>';
++$stackid;
?>

Hello people, i made a button called "button_c.png" to submit the data in forms. I want to submit a form depending on its name or id when the button which is in that form is clicked. This code is not working. Please help me out.

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7 Years
Discussion Span
Last Post by sudeepjd
0

In order to use the image as a submit button, instead of using the <a href="..."> Use <input type="image" src="buttons/button_c.png" border="0" /> This way you do not require the javascript either. The form in whichever the image is in will be submitted.

Edited by sudeepjd: n/a

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