Member Avatar for mtvaran

Hi guys, i have a big problem on these creation. basically if i enter the No of Question then it has to be created No of cells for entering marks.

Eg: No of question = 4 then

quesNO-------Marks
1------------------cell
2------------------cell
3------------------cell
4------------------cell


if anyone of you could help me with this code please!!!!!!!!! hope this would not be too dificult for you guys. Thanks

Edited by mtvaran because: n/a
  • 3 Contributors
  • 6 Replies
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  • 3 Days Discussion Span
  • Latest Post Latest Post by monica singh

Recommended Answers

All 6 Replies

Member Avatar for ko ko

Well, how do you want to get the number of question ( pass the value via submitting the form or generating by javascript DOM element without page loading )

You can simply create text field automatically by using 'for loop' in both PHP and Javascript. Some examples:

In PHP:

$question = $x;
for($i=0;$i<$x;$i++){
	echo '--------------------- cell<br />';
}
In Javascript:

var question = x;
for(i=0;i<x;i++){
	document.write('---------------cell<br />');
}

'$x' and 'x' are the variables for the number of questions.

Member Avatar for monica singh

hi dear,
Here is the complete code.

<html>
<head></head><body>
<form method="POST" action="only_check.php">
Enter the number of question
<input type="text" name="question">
<input type="submit">
</form>


<?php
$value=$_POST['question'];

for($i=0;$i<$value;$i++)
{
echo '<input type="text"  style="position:absolute;border:1px #C0C0C0 solid;background-color:#C0FFFF;font-family:Courier New;font-size:13px;"  >'."<br/>";
}

?>
</body></html>
Member Avatar for mtvaran

Thanks for your codes. could you please provide the code that once i create two cells (text field)then i have to store in database table the value from the text field. im bit new & stupid with PHP so please bear with me. thanx

Edited by mtvaran because: n/a
Member Avatar for mtvaran

hi, here im able to create text field but couldn't insert the data. so could anyone please check this code for me.

<?php 
$value=$_POST['question']; 

for($i=0;$i<$value;$i++) 
{ 
echo "Question NO:"; 
echo '<input type="text" name="qno[]">'."\t"; 

echo "Enter Marks:"; 
echo '<input type="text" name="marks[]">'."\t"; 
echo "<br>"; 
} 
?> 
</form> 
<form name="form1" method="post" action="cellresult.php"> 
  <label> 
  <input type="submit" name="Submit" value="Submit"> 
  </label> 
</form> 

</body>

cellresult.php

<body> 
<?php 
$con = mysql_connect("localhost","root",""); 
if (!$con) 
  { 
  die('Could not connect: ' . mysql_error()); 
  } 

mysql_select_db("test", $con); 

$sql="INSERT INTO cell (QNO,MARKS) 
VALUES 
('$_POST['qno']','$_POST['marks']')"; 

if (!mysql_query($sql,$con)) 
  { 
  die('Error: ' . mysql_error()); 
  } 
echo "1 record added"; 

mysql_close($con) 
?> 
</body>
Member Avatar for ko ko

<?php
$value=$_POST;

for($i=0;$i<$value;$i++)
{
echo "Question NO:";
echo '<input type="text" name="qno[]">'."\t";

echo "Enter Marks:";
echo '<input type="text" name="marks[]">'."\t";
echo "<br>";
}
?>
</form>
<form name="form1" method="post" action="cellresult.php">
<label>
<input type="submit" name="Submit" value="Submit">
</label>
</form>

</body>

Fields are out of the form. Try with this one.

<form name="form1" method="post" action="cellresult.php"> 
<?php
	if(isset($_POST['question'])){
		$value=$_POST['question']; 
		for($i=0;$i<$value;$i++) 
		{ 
		echo "Question NO:"; 
		echo '<input type="text" name="qno[]">'."\t"; 

		echo "Enter Marks:"; 
		echo '<input type="text" name="marks[]">'."\t"; 
		echo "<br>"; 
		}
	}
	else{
		echo "No question.";
	}
?> 
  <input type="submit" name="Submit" value="Submit"> 
</form>
Member Avatar for monica singh

Hi, dear

just tell me your whole query what you want to do, how many fields are there in your table and also their name.

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