Hello
I'm trying to name a uploaded image to my website with a random number / letter combination
and if the number it generates is taken it makes a new one untill it finds a free one, then i need to insert the url of the image into a table called photos -> url
how would i name it, and go about it?
Thanks in advanced
Jump to PostWhat have you tried so far?
What have you tried so far?
// make a note of the current working directory, relative to root.
$directory_self = str_replace(basename($_SERVER['PHP_SELF']), '', $_SERVER['PHP_SELF']);
// make a note of the directory that will recieve the uploaded files
$uploadsDirectory = $_SERVER['DOCUMENT_ROOT'] . $directory_self . 'photos/';
// make a note of the location of the upload form in case we need it
$uploadForm = 'http://' . $_SERVER['HTTP_HOST'] . $directory_self . 'uploadform.php';
// make a note of the location of the success page
$uploadSuccess = 'http://' . $_SERVER['HTTP_HOST'] . $directory_self . 'uploaded.php';
// name of the fieldname used for the file in the HTML form
$fieldname = 'file';
//echo'<pre>';print_r($_FILES);exit;
// Now let's deal with the uploaded files
// possible PHP upload errors
$errors = array(1 => 'php.ini max file size exceeded',
2 => 'html form max file size exceeded',
3 => 'file upload was only partial',
4 => 'no file was attached');
// check the upload form was actually submitted else print form
isset($_POST['submit'])
or error('the upload form is neaded', $uploadForm);
// check if any files were uploaded and if
// so store the active $_FILES array keys
$active_keys = array();
foreach($_FILES[$fieldname]['name'] as $key => $filename)
{
if(!empty($filename))
{
$active_keys[] = $key;
}
}
// check at least one file was uploaded
count($active_keys)
or error('No files were uploaded', $uploadForm);
// check for standard uploading errors
foreach($active_keys as $key)
{
($_FILES[$fieldname]['error'][$key] == 0)
or error($_FILES[$fieldname]['tmp_name'][$key].': '.$errors[$_FILES[$fieldname]['error'][$key]], $uploadForm);
}
// check that the file we are working on really was an HTTP upload
foreach($active_keys as $key)
{
@is_uploaded_file($_FILES[$fieldname]['tmp_name'][$key])
or error($_FILES[$fieldname]['tmp_name'][$key].' not an HTTP upload', $uploadForm);
}
// validation... since this is an image upload script we
// should run a check to make sure the upload is an image
foreach($active_keys as $key)
{
@getimagesize($_FILES[$fieldname]['tmp_name'][$key])
or error($_FILES[$fieldname]['tmp_name'][$key].' not an image', $uploadForm);
}
// make a unique filename for the uploaded file and check it is
// not taken... if it is keep trying until we find a vacant one
foreach($active_keys as $key)
{
$now = time();
while(file_exists($uploadFilename[$key] = $uploadsDirectory.$now.'-'.$_FILES[$fieldname]['name'][$key]))
{
$now++;
}
}
// now let's move the file to its final and allocate it with the new filename
foreach($active_keys as $key)
{
@move_uploaded_file($_FILES[$fieldname]['tmp_name'][$key], $uploadFilename[$key])
or error('receiving directory insuffiecient permission', $uploadForm);
}
echo $_FILES[$fieldname]['tmp_name'], $uploadFilename[$key];
$update = mysql_query('UPDATE photos SET url=');
// If you got this far, everything has worked and the file has been successfully saved.
// We are now going to redirect the client to the success page.
//header('Location: ' . $uploadSuccess);
// make an error handler which will be used if the upload fails
function error($error, $location, $seconds = 5)
{
header("Refresh: $seconds; URL=\"$location\"");
echo '<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN"'."\n".
'"http://www.w3.org/TR/html4/strict.dtd">'."\n\n".
'<html lang="en">'."\n".
' <head>'."\n".
' <meta http-equiv="content-type" content="text/html; charset=iso-8859-1">'."\n\n".
' <link rel="stylesheet" type="text/css" href="stylesheet.css">'."\n\n".
' <title>Upload error</title>'."\n\n".
' </head>'."\n\n".
' <body>'."\n\n".
' <div id="Upload">'."\n\n".
' <h1>Upload failure</h1>'."\n\n".
' <p>An error has occured: '."\n\n".
' <span class="red">' . $error . '...</span>'."\n\n".
' The upload form is reloading</p>'."\n\n".
' </div>'."\n\n".
'</html>';
exit;
} // end error handleri have no idea how i can get the url, ive tryed some things, youll see theres a query there, missing the url id put in the database
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