0

I am sorry but I am just starting and I suck. I've been spending the last hour on the site trying to use others' threads and the FAQ to fix this but I simply have not been able to do so. This is real simple. All my code is..

<?php

include 'connect.php';

$get = mysql_query("SELECT * FROM songs");
while ($row = mysql_fetch_assoc($get))
{
 //get data
 $song = $row['song'];
 $rating = $row['rating'];

 echo "$song - $rating";

}


?>

where connect.php has mysql_connect and mysql_select_db


and I get "Warning: mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in /home/rbnstuff/public_html/newlayout/index.php on line 6"

3
Contributors
4
Replies
5
Views
6 Years
Discussion Span
Last Post by atalkingfish
1

Probably, $get has NULL. Check the query again. And are you sure that the connection succeed ? Make sure your mysql_connect passed or not. Anyway, use the error handler.

mysql_connect($host, $user, $pass) or die('Couldn\'t connect to MySQL. Error: ' . mysql_error());

SELECT * FROM songs, check this query manually in PHPMyAdmin via the browser.

0

So I ended up replacing the username password type database stuff and it worked. I'm not sure why.

I ended up using this to make the rating system from phpacademy and am wondering how one would get it so an IP wouldn't be able to rate twice. Where should I go for this?

0

Don't rely on IP - ISPs can change this without the user being aware, also many users can share the same IP. A user_id with a login system would be better.

This question has already been answered. Start a new discussion instead.
Have something to contribute to this discussion? Please be thoughtful, detailed and courteous, and be sure to adhere to our posting rules.