Member Avatar for davy_yg 
var_dump(explode(".", $data['image']));
$file[0] = explode(".", $data['image']);
echo $file[0];

The result:

array(2) { [0]=> string(6) "image2" [1]=> string(3) "jpg" } Array

I am trying to store "image2" in $file, how? (exclude the jpg)

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  • Latest Post Latest Post by radow
Member Avatar for radow

You will be able to use function pathinfo(), If want get filename without it extension.
For example:

echo pathinfo("test.jpeg", PATHINFO_FILENAME);// show test
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