0

I am using codeigniter 2.1.2 and Bootstrap.

I am opening a form in a modal window.

The form is inside a div with id status.

The form has a few input fields and an upload file field.

I am trying to submit the form with ajaxForm.

In my controller I echo "success" if everything is fine.

public function edit($provinceId, $bookId, $id = NULL)
{
    $province = $this->province_m->get($provinceId);
    $book = $this->book_m->get($bookId);

    if($id)
    {
        $this->data['issue'] = $this->issue_m->get($id);
        count($this->data['issue']) || $this->data['errors'][] = 'The issue could not be found.';
    }
    else
    {
        $this->data['issue'] = $this->issue_m->get_new();
    }

    // Set up the form
    $rules = $this->issue_m->rules;
    $this->form_validation->set_rules($rules);

    // Checks if issue save was pressed, otherwise it will show the errors becuase of the post of province and book
    if($this->input->post('issueposted') != '')
    {
        if ($this->form_validation->run() == TRUE)
        {
            $data = $this->issue_m->array_from_post(array('mag_folder'));
            $data['province_id'] = $provinceId;
            $data['book_id'] = $bookId;
            $data['publish_date'] = mdate('%Y-%m-%d', strtotime($this->input->post('publish_date')));

            if($_FILES['image']['error'] === 0)
            {
                      $uploaded = $this->do_upload($province->folder, $book->name);

              if($uploaded)
              {
                $data['image'] = $this->upload->file_name;
                $this->issue_m->save($data, $id);
                echo "success";
              }
            }
            else //No file to upload
            {
                  $this->issue_m->save($data, $id);
              echo "success";
            }
          }
        }

        // Load the view
        $this->data['url'] = site_url('admin/issue/edit') . '/' . $province->id . '/' . $book->id . '/' . $id;
        $this->data['province'] = $province;
        $this->data['book'] = $book;
        $data = $this->load->view('admin/issue/edit', $this->data, TRUE);
        $this->output->set_output($data);
    }
}

The javascript:

$(function() {
var options = { 
        target: '#status',
        success: function(data) { 
            alert(data);
            window.location.replace("http://thinklocal.dev/admin/province");
    }
}; 

// pass options to ajaxForm 
$('#issueform').ajaxForm(options);
});

Everything worked fine besides the fact that the page was not redirecting on success.
When I alert the data I get this: success<div id="status">

I also tried this way, but here when I click the submit button, nothing happens.

$('#issueform').submit( function()
 {
   var bar = $('.bar');
   var percent = $('.percent');
   var status = $('#status');

   $(this).ajaxForm({
     beforeSend: function() {
       status.html();
       var percentVal = '0%';
       bar.width(percentVal)
       percent.html(percentVal);
     },
     uploadProgress: function(event, position, total, percentComplete) {
       var percentVal = percentComplete + '%';
       bar.width(percentVal)
       percent.html(percentVal);
     },
     success: function(xhr) { 
       status.html(xhr.responseText); 
     }
    return false;
   });
 });  

Can someone please help me figure out how do I submit the form and redirect if there are no errors, or go back to the modal window if there are errors?

2
Contributors
3
Replies
40
Views
4 Years
Discussion Span
Last Post by cgull
0

Can someone please help me figure out how do I submit the form and redirect if there are no errors, or go back to the modal window if there are errors?

I'm not sure what you wrote here:

$('#issueform').submit( function()
{
var bar = $('.bar');
var percent = $('.percent');
var status = $('#status');
$(this).ajaxForm({
beforeSend: function() {
status.html();
var percentVal = '0%';
bar.width(percentVal)
percent.html(percentVal);
},
uploadProgress: function(event, position, total, percentComplete) {
var percentVal = percentComplete + '%';
bar.width(percentVal)
percent.html(percentVal);
},
success: function(xhr) {
status.html(xhr.responseText);
}
return false;
});
}); 

I don't know your form ID so it should look like this:

$('#issueform').on('submit', 'form', function(e){
e.preventDefault();
var bar = $('#bar').val();
var percent = $('#percent').val();
var status = $('#status').val();

$.ajax({
    type: "POST", 
    secureuri: false,
    url: base_url+"file/",   
    data: {
    'bar': $('#bar').val()
    'percent': $('#percent').val()
    'status': $('#status').val()
    },
    success: function(data){
        $('#files').html(data);
    },
    error: function(){alert('error');}
});     
});

<form method="POST" action='#' id='issueform' >
<input type="text" name="bar" id="bar">
<input type="text" name="percent" id="percent">
<input type="text" name="status" id="status">
<input type="submit" value="submit" id='Submit'>
</form>

You can take a look at upload class for CodeIgniter:

http://ellislab.com/codeigniter/user-guide/libraries/file_uploading.html

and also look at this tutorial regarding about AJAX:

http://net.tutsplus.com/tutorials/javascript-ajax/how-to-upload-files-with-codeigniter-and-ajax/

Edited by LastMitch: grammer

0

Thanks, but your way will not work for a form that needs file uploading.

and the tutorial you sent is a bit old and does not work with the jquery version I am using.

My form id is issueform.

2

Found the solution:

In the jquery I changed to success function:

var options = { 
        target: '#status',
        success: function(data) {
            if(data == 'success')
            {
                $('#status').hide();
                window.location.replace("http://thinklocal.dev/admin/province");
            }
    },
        error: function ajaxError(request, type, errorThrown)
{
    var message = "There was an error with the AJAX request.\n";
    switch (type) {
        case 'timeout':
            message += "The request timed out.";
            break;
        case 'notmodified':
            message += "The request was not modified but was not retrieved from the cache.";
            break;
        case 'parsererror':
            message += "XML/Json format is bad.";
            break;
        default:
            message += "HTTP Error (" + request.status + " " + request.statusText + ").";
    }
    message += "\n";
    alert(message);
} 
}; 

// pass options to ajaxForm 
$('#issueform').ajaxForm(options);

In my controller, if there are no errors in the form I echo success and return true:

echo "success";
return true;
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