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Hello,
I have two tables one for 'users' and another for 'vendor_service' in database named 'star'. In vendor_service table i've stored users id as a foreign key. Now if i try to insert values in vendor_service table it shows following error.
Cannot add or update a child row: a foreign key constraint fails (star/vendor_service, CONSTRAINT vendor_service_ibfk_1 FOREIGN KEY (id) REFERENCES users (id)).

My Code is here:

<form class="form-horizontal" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
  <fieldset>
    <legend>Add Service</legend>
    <label class="control-label" for="inputWarning">Service Name</label>
    <input type="text" id="inputWarning" name="s_name" value="<?php echo $s_name; ?>" />
    <label class="control-label" for="inputWarning">Service Category</label>
    <select id="selectError" data-rel="chosen" name="s_ctgry" />
    <option value="Sound">Sound</option>
    <option value="Set&Dom">Set & Dom</option>
    <option value="Transport">Transport</option>
    </select>
    <label class="control-label" for="inputWarning">Service Description</label>
    <textarea name="s_desc" rows="4" value="<?php echo $s_desc; ?>" />
    </textarea>
    <label class="control-label" for="inputWarning">Unit Price</label>
    <input type="text" id="inputWarning" name="s_unt_price" value="<?php echo $s_unt_price; ?>" />
    <label class="control-label" for="inputWarning">Bulk Price</label>
    <input type="text" id="inputWarning" name="s_blk_price" value="<?php echo $s_blk_price; ?>" />
    <button type="submit" class="btn btn-primary" name="insert">Insert Service</button>
    <button type="reset" class="btn">Cancel</button>
  </fieldset>
</form>
<?php
    if ( isset( $_POST['insert'] ) ) 
    {
        require('include/conn.php'); //include db connection
        $s_name = mysql_real_escape_string(htmlspecialchars($_POST['s_name']));
            $s_ctgry = htmlspecialchars($_POST['s_ctgry']);
        $s_desc = mysql_real_escape_string(htmlspecialchars($_POST['s_desc']));
        $s_unt_price = mysql_real_escape_string(htmlspecialchars($_POST['s_unt_price']));
        $s_blk_price = mysql_real_escape_string(htmlspecialchars($_POST['s_blk_price']));
        $check = "SELECT * FROM vendor_service WHERE s_name='$s_name'";
        $run = mysql_query($check);
        if ( $s_name == '' ){
            echo"Insert Service Name Please</br>";
            exit();
        }
        else if(mysql_num_rows($run) > 0)
        {
            echo "<script>alert('Service $s_name Already Exist, Please Insert different name')</script>";
            }
        else if( $s_ctgry == '' ){
            echo"Select Category Please</br>";
            exit();
        } 
        else if( $s_desc == '' ){
            echo"Description Please</br>";
            exit();
        }
        else if( $s_unt_price == '' ){
            echo"unit price Please</br>";
            exit();
        }
        else
        {
            $query = "INSERT into vendor_service (s_name, s_ctgry, s_desc, s_unt_price, s_blk_price) 
            values('$s_name', '$s_ctgry', '$s_desc', '$s_unt_price', '$s_blk_price')";
            if( mysql_query ( $query ) or die(mysql_error()) ){
                echo "<script>alert('Service added')</script>"; //put s_prchs_dt varification here
                //header("Location: addservices.php");
            }
            else
            {
                echo"<script>alert('There's some problem Some problem')</script>";
            }
        }
    }
?>
2
Contributors
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3 Years
Discussion Span
Last Post by diafol
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I assume that you're talking about line56. In order to insert a record you need to include an user_id otherwise why did you include a constraint in the first place? Are these tables related or not? If not pull the user_id field. I haven't studied your code too closely, but sometimes we can create what's called a link table. I don't think that is applicable here though as you need a 1 to many relationship. IMO.

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Table 'users' is my master table in which 'id' is primary key and another table 'vendor_service' has 'id' as a foreign key. If user is logged in and try to insert values in vendor_service, i want id should be automatically inserted in vendor_service table from the user's id through which currently signed in.

Edited by Nilesh_2: Table Images Uploaded

Attachments New_Picture_(5).jpg 139.8 KB
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That was not your original question or the subject of the title. In fact you didn't pose a question.

So - what's the problem with including a user_id from the session into your insert query?

Edited by diafol

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The problem is that I'm getting following error when i execute above query...

Error : Cannot add or update a child row: a foreign key constraint fails (star/vendor_service, CONSTRAINT vendor_service_ibfk_1 FOREIGN KEY (id) REFERENCES users (id)).

What is solution to this error ?

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As I said, you haven't included the user_id in the INSERT query. Get the user_id value from your session variables and include it. You say that you have a login procedure ("If user is logged in...") so I assume that you're storing the user_id in a session.

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